XSLT: How to change an attribute value during <xsl-第2页回答

I have an XML document, and I want to change the values for one of the attributes.

First I copied everything from input to output using:

<xsl:template match="@*|node()">
  <xsl:copy>
    <xsl:apply-templates select="@*|node()"/>
  </xsl:copy>
</xsl:template>

And now I want to change the value of the attribute "type" in any element named "property".

标签： xslt

8条回答

欢心

2楼-- · 2019-01-06 12:36

The top two answers will not work if there is a xmlns definition in the root element:

<?xml version="1.0"?>
<html xmlns="http://www.w3.org/1999/xhtml">
    <property type="old"/>
</html>

All of the solutions will not work for the above xml.

The possible solution is like:

<?xml version="1.0"?> 

<xsl:stylesheet xmlns:xsl="http://www.w3.org/1999/XSL/Transform" version="1.0">

  <xsl:output omit-xml-declaration="yes" indent="yes"/>
  <xsl:template match="node()[local-name()='property']/@*[local-name()='type']">
      <xsl:attribute name="{name()}" namespace="{namespace-uri()}">
                some new value here
          </xsl:attribute>
  </xsl:template>

  <xsl:template match="@*|node()|comment()|processing-instruction()|text()">
      <xsl:copy>
          <xsl:apply-templates select="@*|node()|comment()|processing-instruction()|text()"/>
      </xsl:copy>
  </xsl:template>
</xsl:stylesheet>

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Root（大扎）

3楼-- · 2019-01-06 12:37

I had a similar case where I wanted to delete one attribute from a simple node, and couldn't figure out what axis would let me read the attribute name. In the end, all I had to do was use

@*[name(.)!='AttributeNameToDelete']

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