Uploading multiple files with Flask

Question

Is there a way to receive multiple uploaded files with Flask? I've tried the following:

<form method="POST" enctype="multipart/form-data" action="/upload">
  <input type="file" name="file[]" multiple="">
  <input type="submit" value="add">
</form>

And then printed the contents of request.files['file']:

@app.route('/upload', methods=['POST'])
def upload():
  if not _upload_dir:
    raise ValueError('Uploads are disabled.')

  uploaded_file = flask.request.files['file']
  print uploaded_file
  media.add_for_upload(uploaded_file, _upload_dir)
  return flask.redirect(flask.url_for('_main'))

If I upload multiple files, it only prints the first file in the set:

<FileStorage: u'test_file.mp3' ('audio/mp3')>  

Is there a way to receive multiple files using Flask's built-in upload handling? Thanks for any help!

Answer 1

Using Flask 1.0.2:

files = request.files.getlist("images")

Where images is the key of the key/value pair. With the Value being the multiple images.

Answer 2

You can use method getlist of flask.request.files, for example:

@app.route("/upload", methods=["POST"])
def upload():
    uploaded_files = flask.request.files.getlist("file[]")
    print uploaded_files
    return ""

Answer 3

For those who are still searching for the solution to this problem please refer to this answer because the above answers did not work for me this is a working solution for flask version '1.0.2':

images = request.files.to_dict() #convert multidict to dict
for image in images:     #image will be the key 
    print(images[image])        #this line will print value for the image key
    file_name = images[image].filename
    images[image].save(some_destination)

basically, images[image] has an image file with save function added to it Now do whatever you like to do with the data.