At the moment I'm working through "Practical Common Lisp" from Peter Seibel.
In the chapter "Practical: A Simple Database" (http://www.gigamonkeys.com/book/practical-a-simple-database.html) Seibel explains keyword parameters and the usage of a supplied-parameter with the following example:
(defun foo (&key a (b 20) (c 30 c-p)) (list a b c c-p))
Results:
(foo :a 1 :b 2 :c 3) ==> (1 2 3 T)
(foo :c 3 :b 2 :a 1) ==> (1 2 3 T)
(foo :a 1 :c 3) ==> (1 20 3 T)
(foo) ==> (NIL 20 30 NIL)
So if I use &key at the beginning of my parameter list, I have the possibility to use a list of 3 parameters name, default value and the third if the parameter as been supplied or not. Ok. But looking at the code in the above example:
(list a b c c-p)
How does the lisp interpreter know that c-p is my "supplied parameter"?
Let's reindent the function foo:
If you indent it like this you will see that the function has three keyword parameters: a, b and c. These are available in the body of the function.
For the keyword parameter c there is a variable declared c-p that will be T or NIL depending whether c has been passed when foo gets called.
A keyword parameter generally can be declared as one of the following options:
The supplied-p is particularly interesting when one wants to see whether the value comes from the call or the default value:
Now the user can init the elements to NIL:
Here the default value and the supplied value can both be NIL, but we need to make a difference. The variable init-value-supplied-p makes it possible to see whether the NIL value of the variable init-value comes from the default or from the function call.
It's difficult to tell what you are asking.
c-p
is bound toT
orNIL
, depending on whetherc
is supplied as a parameter. This binding is then available to the body of the function.