I have a bunch of test vectors, presented in the form of hexadecimal strings:
MSG: 6BC1BEE22E409F96E93D7E117393172A
MAC: 070A16B46B4D4144F79BDD9DD04A287C
MSG: 6BC1BEE22E409F96E93D7E117393172AAE2D8A57
MAC: 7D85449EA6EA19C823A7BF78837DFADE
etc. I need to get these into a C++ program somehow, without too much editing required. There are various options:
- Edit the test vectors by hand into the form
0x6B,0xC1,0xBE,...
- Edit the test vectors by hand into the form "6BC1BEE22E409F96E93D7E117393172A" and write a function to convert that into a byte array at run time.
- Write a program to parse the test vectors and output C++ code.
But the one I ended up using was:
- User-defined literals,
because fun. I defined a helper class HexByteArray
and a user-defined literal operator HexByteArray operator "" _$ (const char* s)
that parses a string of the form "0xXX...XX"
, where XX...XX
is an even number of hex digits. HexByteArray
includes conversion operators to const uint8_t*
and std::vector<uint8_t>
. So now I can write e.g.
struct {
std::vector<uint8_t> MSG ;
uint8_t* MAC ;
} Test1 = {
0x6BC1BEE22E409F96E93D7E117393172A_$,
0x070A16B46B4D4144F79BDD9DD04A287C_$
} ;
Which works nicely. But now here is my question: Can I do this for arrays as well? For instance:
uint8_t MAC[16] = 0x070A16B46B4D4144F79BDD9DD04A287C_$ ;
or even
uint8_t MAC[] = 0x070A16B46B4D4144F79BDD9DD04A287C_$ ;
I can't see how to make this work. To initialise an array, I would seem to need an std::initializer_list
. But as far as I can tell, only the compiler can instantiate such a thing. Any ideas?
Here is my code:
HexByteArray.h
#include <cstdint>
#include <vector>
class HexByteArray
{
public:
HexByteArray (const char* s) ;
~HexByteArray() { delete[] a ; }
operator const uint8_t*() && { const uint8_t* t = a ; a = 0 ; return t ; }
operator std::vector<uint8_t>() &&
{
std::vector<uint8_t> v ( a, a + len ) ;
a = 0 ;
return v ;
}
class ErrorInvalidPrefix { } ;
class ErrorHexDigit { } ;
class ErrorOddLength { } ;
private:
const uint8_t* a = 0 ;
size_t len ;
} ;
inline HexByteArray operator "" _$ (const char* s)
{
return HexByteArray (s) ;
}
HexByteArray.cpp
#include "HexByteArray.h"
#include <cctype>
#include <cstring>
HexByteArray::HexByteArray (const char* s)
{
if (s[0] != '0' || toupper (s[1]) != 'X') throw ErrorInvalidPrefix() ;
s += 2 ;
// Special case: 0x0_$ is an empty array (because 0x_$ is invalid C++ syntax)
if (!strcmp (s, "0"))
{
a = nullptr ; len = 0 ;
}
else
{
for (len = 0 ; s[len] ; len++) if (!isxdigit (s[len])) throw ErrorHexDigit() ;
if (len & 1) throw ErrorOddLength() ;
len /= 2 ;
uint8_t* t = new uint8_t[len] ;
for (size_t i = 0 ; i < len ; i++, s += 2)
sscanf (s, "%2hhx", &t[i]) ;
a = t ;
}
}
Use a numeric literal operator template, with the signature:
Also, since the data is known at compile-time, we might as well make everything
constexpr
. Note that we usestd::array
instead of C-style arrays:Demo
Example usage:
As a side note,
$
in an identifier is actually a gcc extension, so it's non-standard C++. Consider using a UDL other than_$
.This will make it
Live demo