I researched over the internet, but could not find anything...
I have a mysql db, and records at a table, and I need to get random record from this table at every page load. how can I do that? Is there any func for that?
Appreciate! thanks
SORTED: link: http://www.derekallard.com/blog/post/ordering-database-results-by-random-in-codeigniter/
$this->db->select('name');
$query = $this->db->get('table');
$shuffled_query = $query->result_array();
shuffle ($shuffled_query);
foreach ($shuffled_query as $row) {
echo $row['name'] . '<br />';
}
Do you know how many records there are in the table? You could do something like this:
then:
I think this is not best way. For sample, you've deleted record which is
now==$count
. You must iterate this formysql_num_rows()
Getting random record from large table is very expensive. Don't use
ORDER BY RAND()
.This is a bad idea, but if you have a small table no problem. In a huge databases this type of queries very slow.
This function retrieve all rows in table in random order
This code snippet worked well for me.
Lets think we have table where we deleted some rows. There is maybe ID not continues correctly. For sample id: 1,5,24,28,29,30,31,32,33 (9 rows)
mysql_num_rows returns 9
Another methods will return not existing rows: $count=9; //because mysql_num_rows()==9 $count=rand(1,$count); // returns 4 for sample, but we havn't row with id=4
But with my method you always get existing rows. You can separate code and use first 2 code anywhere on site.