I have a module that is included in another module, and they both implement the same method. I would like to stub the method of the included module, something like this:
module M
def foo
:M
end
end
module A
class << self
include M
def foo
super
end
end
end
describe "trying to stub the included method" do
before { allow(M).to receive(:foo).and_return(:bar) }
it "should be stubbed when calling M" do
expect(M.foo).to eq :bar
end
it "should be stubbed when calling A" do
expect(A.foo).to eq :bar
end
end
The first test is passing, but the second one outputs:
Failure/Error: expect(A.foo).to eq :bar
expected: :bar
got: :M
Why isn't the stub working in this case? Is there a different way to achieve this?
Thanks!
-------------------------------------UPDATE----------------------------------
Thanks! using allow_any_instance_of(M) solved this one. My next question is - what happens if I use prepend and not include? see the following code:
module M
def foo
super
end
end
module A
class << self
prepend M
def foo
:A
end
end
end
describe "trying to stub the included method" do
before { allow_any_instance_of(M).to receive(:foo).and_return(:bar) }
it "should be stubbed when calling A" do
expect(A.foo).to eq :bar
end
end
This time, using allow_any_instance_of(M) results in an infinite loop. why is that?
Note you cannot directly call
M.foo
! Your code only seems to work because you mockedM.foo
to return:bar
.When you open
A
metaclass (class << self
) to includeM
, you have to mock any instance ofM
, that is adding to yourbefore
block:allow_any_instance_of(M).to receive(:foo).and_return(:bar)