Python: import _io

Question

I'm trying to determine which files in the Python library are strictly necessary for my script to run. Right now I'm trying to determine where _io.py is located. In io.py (no underscore), the _io.py module (with underscore) is imported on line 60.

Answer 1

Some modules are compiled directly into the interpreter -- there are no files corresponding to them. You can retrieve a list of these modules from sys.builtin_module_names. In my Pyton 3.1 installation, _io is included in this list.

You might want to have a look at snakefood to determine the dependencies of your script.

Answer 2

Try the DLLs folder under your base python install directory if you are on windows. It contains .pyd modules Ignacio mentions. I had a similar problem with a portable install. Including the DLLs folder contents to my install fixed it. I am using python 2.5.

Answer 3

Not all Python modules are written in Python. Try looking for _io.so or _io.pyd.

Answer 4

From python-list email archive: is "_io.py" missing from 2.7.4 ?, the situation for Python 2 and 3 is different:

In Python 2.7:

To find where the _io module lives, at the interactive interpreter run this:

import _io

_io.__file__

Under Linux, you should get something like this:

'/usr/local/lib/python2.7/lib-dynload/_io.so'

and the equivalent under Windows.

In Python 3:

Note that in Python 3.3, the _io module is now built-in into the compiler, so _io.__file__ no longer exists.