Function to convert column number to letter?

Question

Does anyone have an Excel VBA function which can return the column letter(s) from a number?

For example, entering 100 should return CV.

Answer 1

Here, a simple function in Pascal (Delphi).

function GetColLetterFromNum(Sheet : Variant; Col : Integer) : String;
begin
  Result := Sheet.Columns[Col].Address;  // from Col=100 --> '$CV:$CV'
  Result := Copy(Result, 2, Pos(':', Result) - 2);
end;

Answer 2

This formula will give the column based on a range (i.e., A1), where range is a single cell. If a multi-cell range is given it will return the top-left cell. Note, both cell references must be the same:

MID(CELL("address",A1),2,SEARCH("$",CELL("address",A1),2)-2)

How it works:

CELL("property","range") returns a specific value of the range depending on the property used. In this case the cell address. The address property returns a value $[col]$[row], i.e. A1 -> $A$1. The MID function parses out the column value between the $ symbols.

Answer 3

If you'd rather not use a range object:

Function ColumnLetter(ColumnNumber As Long) As String
    Dim n As Long
    Dim c As Byte
    Dim s As String

    n = ColumnNumber
    Do
        c = ((n - 1) Mod 26)
        s = Chr(c + 65) & s
        n = (n - c) \ 26
    Loop While n > 0
    ColumnLetter = s
End Function

Answer 4

what about just converting to the ascii number and using Chr() to convert back to a letter?

col_letter = Chr(Selection.Column + 96)

Answer 5

Function fColLetter(iCol As Integer) As String
  On Error GoTo errLabel
  fColLetter = Split(Columns(lngCol).Address(, False), ":")(1)
  Exit Function
errLabel:
  fColLetter = "%ERR%"
End Function

Answer 6

Here is a late answer, just for simplistic approach using Int() and If in case of 1-3 character columns:

Function outColLetterFromNumber(i As Integer) As String

    If i < 27 Then       'one-letter
        col = Chr(64 + i)
    ElseIf i < 677 Then  'two-letter
        col = Chr(64 + Int(i / 26)) & Chr(64 + i - (Int(i / 26) * 26))
    Else                 'three-letter
        col = Chr(64 + Int(i / 676)) & Chr(64 + Int(i - Int(i / 676) * 676) / 26)) & Chr(64 + i - (Int(i - Int(i / 676) * 676) / 26) * 26))
    End If

    outColLetterFromNumber = col

End Function