A Java collection of value pairs? (tuples?)

2018-12-31 08:39发布

I like how Java has a Map where you can define the types of each entry in the map, for example <String, Integer>.

What I'm looking for is a type of collection where each element in the collection is a pair of values. Each value in the pair can have its own type (like the String and Integer example above), which is defined at declaration time.

The collection will maintain its given order and will not treat one of the values as a unique key (as in a map).

Essentially I want to be able to define an ARRAY of type <String,Integer> or any other 2 types.

I realize that I can make a class with nothing but the 2 variables in it, but that seems overly verbose.

I also realize that I could use a 2D array, but because of the different types I need to use, I'd have to make them arrays of OBJECT, and then I'd have to cast all the time.

I only need to store pairs in the collection, so I only need two values per entry. Does something like this exist without going the class route? Thanks!

标签: java
17条回答
余生请多指教
2楼-- · 2018-12-31 09:15

I mean, even though there is no Pair class in Java there is something pretty simmilar: Map.Entry

Map.Entry Documentation

This is (simplifying quite a bit) what HashMap , or actually any Map stores.

You can create an instance of Map store your values in it and get the entry set. You will end up with a Set<Map.Entry<K,V>> which effectively is what you want.

So:

public static void main(String []args)
{    
    HashMap<String, Integer> values = new HashMap<String,Integer>();
    values.put("A", 235);//your custom data, the types may be different
    //more data insertions....
    Set<Map.Entry<String,Integer>> list = values.entrySet();//your list 
    //do as you may with it
}
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明月照影归
3楼-- · 2018-12-31 09:16

Apache common lang3 has Pair class and few other libraries mentioned in this thread What is the equivalent of the C++ Pair<L,R> in Java?

Example matching the requirement from your original question:

List<Pair<String, Integer>> myPairs = new ArrayList<Pair<String, Integer>>();
myPairs.add(Pair.of("val1", 11));
myPairs.add(Pair.of("val2", 17));

//...

for(Pair<String, Integer> pair : myPairs) {
  //following two lines are equivalent... whichever is easier for you...
  System.out.println(pair.getLeft() + ": " + pair.getRight());
  System.out.println(pair.getKey() + ": " + pair.getValue());
}
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初与友歌
4楼-- · 2018-12-31 09:19

AbstractMap.SimpleEntry

Easy you are looking for this:

java.util.List<java.util.Map.Entry<String,Integer>> pairList= new java.util.ArrayList<>();

How can you fill it?

java.util.Map.Entry<String,Integer> pair1=new java.util.AbstractMap.SimpleEntry<>("Not Unique key1",1);
java.util.Map.Entry<String,Integer> pair2=new java.util.AbstractMap.SimpleEntry<>("Not Unique key2",2);
pairList.add(pair1);
pairList.add(pair2);

This simplifies to:

Entry<String,Integer> pair1=new SimpleEntry<>("Not Unique key1",1);
Entry<String,Integer> pair2=new SimpleEntry<>("Not Unique key2",2);
pairList.add(pair1);
pairList.add(pair2);

And, with the help of a createEntry method, can further reduce the verbosity to:

pairList.add(createEntry("Not Unique key1", 1));
pairList.add(createEntry("Not Unique key2", 2));

Since ArrayList isn't final, it can be subclassed to expose an of method (and the aforementioned createEntry method), resulting in the syntactically terse:

TupleList<java.util.Map.Entry<String,Integer>> pair = new TupleList<>();
pair.of("Not Unique key1", 1);
pair.of("Not Unique key2", 2);
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弹指情弦暗扣
5楼-- · 2018-12-31 09:19

Java 9+

In Java 9, you can simply write: Map.entry(key, value) to create an immutable pair.

Note: this method does not allow keys or values to be null. If you want to allow null values, for example, you'd want to change this to: Map.entry(key, Optional.ofNullable(value)).


Java 8+

In Java 8, you can use the more general-purpose javafx.util.Pair to create an immutable, serializable pair. This class does allow null keys and null values. (In Java 9, this class is included in the javafx.base module). EDIT: As of Java 11, JavaFX has been decoupled from the JDK, so you'd need the additional maven artifact org.openjfx:javafx-base.


Java 6+

In Java 6 and up, you can use the more verbose AbstractMap.SimpleImmutableEntry for an immutable pair, or AbstractMap.SimpleEntry for a pair whose value can be changed. These classes also allow null keys and null values, and are serializable.


Android

If you're writing for Android, just use Pair.create(key, value) to create an immutable pair.


Apache Commons

Apache Commons Lang provides the helpful Pair.of(key, value) to create an immutable, comparable, serializable pair.


Eclipse Collections

If you're using pairs that contain primitives, Eclipse Collections provides some very efficient primitive pair classes that will avoid all the inefficient auto-boxing and auto-unboxing.

For instance, you could use PrimitiveTuples.pair(int, int) to create an IntIntPair, or PrimitiveTuples.pair(float, long) to create a FloatLongPair.


Project Lombok

Using Project Lombok, you can create an immutable pair class simply by writing:

@Value
public class Pair<K, V> {
    K key;
    V value;
}

Lombok will fill in the constructor, getters, equals(), hashCode(), and toString() methods for you automatically in the generated bytecode. If you want a static factory method instead of a constructor, e.g., a Pair.of(k, v), simply change the annotation to: @Value(staticConstructor = "of").


Otherwise

If none of the above solutions float your boat, you can simply copy and paste the following code (which, unlike the class listed in the accepted answer, guards against NullPointerExceptions):

import java.util.Objects;

public class Pair<K, V> {

    public final K key;
    public final V value;

    public Pair(K key, V value) {
        this.key = key;
        this.value = value;
    }

    public boolean equals(Object o) {
        return o instanceof Pair && Objects.equals(key, ((Pair<?,?>)o).key) && Objects.equals(value, ((Pair<?,?>)o).value);
    }

    public int hashCode() {
        return 31 * Objects.hashCode(key) + Objects.hashCode(value);
    }

    public String toString() {
        return key + "=" + value;
    }
}
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梦该遗忘
6楼-- · 2018-12-31 09:19

This is based on JavaHelp4u 's code.

Less verbose and shows how to do in one line and how to loop over things.

//======>  Imports
import java.util.AbstractMap.SimpleEntry;
import java.util.ArrayList;
import java.util.List;
import java.util.Map.Entry;

//======>  Single Entry
SimpleEntry<String, String> myEntry = new SimpleEntry<String, String>("ID", "Text");
System.out.println("key: " + myEntry.getKey() + "    value:" + myEntry.getValue());
System.out.println();

//======>  List of Entries
List<Entry<String,String>> pairList = new ArrayList<>();

//-- Specify manually
Entry<String,String> firstButton = new SimpleEntry<String, String>("Red ", "Way out");
pairList.add(firstButton);

//-- one liner:
pairList.add(new SimpleEntry<String,String>("Gray", "Alternate route"));  //Ananomous add.

//-- Iterate over Entry array:
for (Entry<String, String> entr : pairList) {
    System.out.println("Button: " + entr.getKey() + "    Label: " + entr.getValue());
}
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美炸的是我
7楼-- · 2018-12-31 09:21

What about com.sun.tools.javac.util.Pair?

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