Convert IP address string to binary in Python

Question

As part of a larger application, I am trying to convert an IP address to binary. Purpose being to later calculate the broadcast address for Wake on LAN traffic. I am assuming that there is a much more efficient way to do this then the way I am thinking. Which is breaking up the IP address by octet, adding 0's to the beginning of each octet where necessary, converting each octet to binary, then combining the results. Should I be looking at netaddr, sockets, or something completely different?

Example: From 192.168.1.1 to 11000000.10101000.00000001.00000001

Answer 1

Define IP address in variable

ipadd = "10.10.20.20"

convert IP address in list

ip = ipadd.split(".")

Now convert IP address in binary numbers

print ('{0:08b}.{1:08b}.{2:08b}. 
    {3:08b}'.format(int(ip[0]),int(ip[1]),int(ip[2]),int(ip[3])))

00001010.00001010.00010100.00010100

Answer 2

Purpose being to later calculate the broadcast address for Wake on LAN traffic

ipaddr (see PEP 3144):

import ipaddr

print ipaddr.IPNetwork('192.168.1.1/24').broadcast
# -> 192.168.1.255

In Python 3.3, ipaddress module:

#!/usr/bin/env python3
import ipaddress

print(ipaddress.IPv4Network('192.162.1.1/24', strict=False).broadcast_address)
# -> 192.168.1.255

To match the example in your question exactly:

# convert ip string to a binary number
print(bin(int(ipaddress.IPv4Address('192.168.1.1'))))
# -> 0b11000000101010000000000100000001

Answer 3

Is socket.inet_aton() what you want?

Answer 4

You can use string format function to convert the numbers to binary. I made this function:

def ip2bin(ip):
    octets = map(int, ip.split('/')[0].split('.')) # '1.2.3.4'=>[1, 2, 3, 4]
    binary = '{0:08b}{1:08b}{2:08b}{3:08b}'.format(*octets)
    range = int(ip.split('/')[1]) if '/' in ip else None
    return binary[:range] if range else binary

This will return a binary IP or IP range, so you can use it to test if an IP is in a range:

>>> ip2bin('255.255.127.0')
'11111111111111110111111100000000'
>>> ip2bin('255.255.127.0/24')
'111111111111111101111111'
>>> ip2bin('255.255.127.123').startswith(ip2bin('255.255.127.0/24'))
True

Answer 5

You think of something like below ?

ip = '192.168.1.1'
print '.'.join([bin(int(x)+256)[3:] for x in ip.split('.')])

I agree with others, you probably should avoid to convert to binary representation to achieve what you want.

Answer 6

IP = '192.168.1.1'

ip2bin =  ".".join(map(str,["{0:08b}".format(int(x)) for x in IP.split(".")]))
print(ip2bin)

output

11000000.10101000.00000001.00000001