Knockout observableArray in TypeScript

2019-03-26 17:21发布

What is the proper way to initialize a Knockout observableArray in a TypeScript class?

I am doing something like this:

   module ViewModel { 

        declare var ko;

        export class IndexPageViewModel {       

                agencies: any;                   

                constructor () {               
                    this.agencies = ko.observableArray([]);              
                }                                                                                                   
        }
    }


var ivm = new ViewModel.IndexPageViewModel();
ivm.agencies.push({name: "name", alias : "alias"});
for (var i = 0; i < ivm.agencies.length; i++){
    alert(ivm.agencies[i].name);
 }

Looks simple enough, but when I attempt to access the agencies property as indicated, execution hangs. Did I miss something?

2条回答
狗以群分
2楼-- · 2019-03-26 17:57

I just did this in TypeScript 1.3 (though it should work in older versions too):

pendingAddAssociations: KnockoutObservableArray<ControllerModel> = ko.observableArray<ControllerModel>([]);

for your example, if you have an Agency class.

export class IndexPageViewModel {

        agencies: KnockoutObservableArray<Agency>;

        constructor () {
            this.agencies = ko.observableArray<Agency>([]);
        }
    }

I've also found that you can cast to any this.agencies = <any>[]; This is useful if you are using the Knockout ES5 plugin.

查看更多
我命由我不由天
3楼-- · 2019-03-26 18:09

This line is where your mistake is:

agencies[i]

When you access an observable array, it is actually wrapped in a function so you do access it like:

agencies()[i]

Also make yourself a favor and download the Knockout definitions from: https://github.com/borisyankov/DefinitelyTyped

Then declare your attributes with types:

module ViewModel {

    export class IndexPageViewModel {

        agencies: KnockoutObservableArray;

        constructor () {
            this.agencies = ko.observableArray([]);
        }
    }
}
查看更多
登录 后发表回答