Get size of String w/ encoding in bytes without co

Question

I have a situation where I need to know the size of a String/encoding pair, in bytes, but cannot use the getBytes() method because 1) the String is very large and duplicating the String in a byte[] array would use a large amount of memory, but more to the point 2) getBytes() allocates a byte[] array based on the length of the String * the maximum possible bytes per character. So if I have a String with 1.5B characters and UTF-16 encoding, getBytes() will try to allocate a 3GB array and fail, since arrays are limited to 2^32 - X bytes (X is Java version specific).

So - is there some way to calculate the byte size of a String/encoding pair directly from the String object?

UPDATE:

Here's a working implementation of jtahlborn's answer:

private class CountingOutputStream extends OutputStream {
    int total;

    @Override
    public void write(int i) {
        throw new RuntimeException("don't use");
    }
    @Override
    public void write(byte[] b) {
        total += b.length;
    }

    @Override public void write(byte[] b, int offset, int len) {
        total += len;
    }
}

Answer 1

Simple, just write it to a dummy output stream:

class CountingOutputStream extends OutputStream {
  private int _total;

  @Override public void write(int b) {
    ++_total;
  }

  @Override public void write(byte[] b) {
    _total += b.length;
  }

  @Override public void write(byte[] b, int offset, int len) {
    _total += len;
  }

  public int getTotalSize(){
     _total;
  }
}

CountingOutputStream cos = new CountingOutputStream();
Writer writer = new OutputStreamWriter(cos, "my_encoding");
//writer.write(myString);

// UPDATE: OutputStreamWriter does a simple copy of the _entire_ input string, to avoid that use:
for(int i = 0; i < myString.length(); i+=8096) {
  int end = Math.min(myString.length(), i+8096);
  writer.write(myString, i, end - i);
}

writer.flush();

System.out.println("Total bytes: " + cos.getTotalSize());

it's not only simple, but probably just as fast as the other "complex" answers.

Answer 2

The same using apache-commons libraries:

public static long stringLength(String string, Charset charset) {

    try (NullOutputStream nul = new NullOutputStream();
         CountingOutputStream count = new CountingOutputStream(nul)) {

        IOUtils.write(string, count, charset.name());
        count.flush();
        return count.getCount();
    } catch (IOException e) {
        throw new IllegalStateException("Unexpected I/O.", e);
    }
}

Answer 3

Here's an apparently working implementation:

import java.nio.charset.Charset;
import java.nio.charset.StandardCharsets;

public class TestUnicode {

    private final static int ENCODE_CHUNK = 100;

    public static long bytesRequiredToEncode(final String s,
            final Charset encoding) {
        long count = 0;
        for (int i = 0; i < s.length(); ) {
            int end = i + ENCODE_CHUNK;
            if (end >= s.length()) {
                end = s.length();
            } else if (Character.isHighSurrogate(s.charAt(end))) {
                end++;
            }
            count += encoding.encode(s.substring(i, end)).remaining() + 1;
            i = end;
        }
        return count;
    }

    public static void main(String[] args) {
        StringBuilder sb = new StringBuilder();
        for (int i = 0; i < 100; i++) {
            sb.appendCodePoint(11614);
            sb.appendCodePoint(1061122);
            sb.appendCodePoint(2065);
            sb.appendCodePoint(1064124);
        }
        Charset cs = StandardCharsets.UTF_8;

        System.out.println(bytesRequiredToEncode(new String(sb), cs));
        System.out.println(new String(sb).getBytes(cs).length);
    }
}

The output is:

1400
1400

In practice I'd increase ENCODE_CHUNK to 10MChars or so.

Probably slightly less efficient than brettw's answer, but simpler to implement.

Answer 4

Ok, this is extremely gross. I admit that, but this stuff is hidden by the JVM, so we have to dig a little. And sweat a little.

First, we want the actual char[] that backs a String without making a copy. To do this we have to use reflection to get at the 'value' field:

char[] chars = null;
for (Field field : String.class.getDeclaredFields()) {
    if ("value".equals(field.getName())) {
        field.setAccessible(true);
        chars = (char[]) field.get(string); // <--- got it!
        break;
    }
}

Next you need to implement a subclass of java.nio.ByteBuffer. Something like:

class MyByteBuffer extends ByteBuffer {
    int length;            
    // Your implementation here
};

Ignore all of the getters, implement all of the put methods like put(byte) and putChar(char) etc. Inside something like put(byte), increment length by 1, inside of put(byte[]) increment length by the array length. Get it? Everything that is put, you add the size of whatever it is to length. But you're not storing anything in your ByteBuffer, you're just counting and throwing away, so no space is taken. If you breakpoint the put methods, you can probably figure out which ones you actually need to implement. putFloat(float) is probably not used, for example.

Now for the grand finale, putting it all together:

MyByteBuffer bbuf = new MyByteBuffer();         // your "counting" buffer
CharBuffer cbuf = CharBuffer.wrap(chars);       // wrap your char array
Charset charset = Charset.forName("UTF-8");     // your charset goes here
CharsetEncoder encoder = charset.newEncoder();  // make a new encoder
encoder.encode(cbuf, bbuf, true);               // do it!
System.out.printf("Length: %d\n", bbuf.length); // pay me US$1,000,000