List of dictionary in python as HTML Table format

2019-03-22 03:46发布

I have list of dictionary as the below format

[{'duration': 0.7, 'project_id': 3, 'resource': u'Arya Stark', 'activity': u'Development'},
{'duration': 0.9, 'project_id': 4, 'resource': u'Ned Stark', 'activity': u'Development'},
{'duration': 2.88, 'project_id': 7, 'resource': u'Robb Stark', 'activity': u'Development'},
{'duration': 0.22, 'project_id': 9, 'resource': u'Jon Snow', 'activity': u'Support'},
{'duration': 0.3, 'project_id': 9, 'resource': u'Jon Snow', 'activity': u'Support'},
{'duration': 2.15, 'project_id': 3, 'resource': u'Arya Stark', 'activity': u'Practise'},
{'duration': 3.35, 'project_id': 4, 'resource': u'Sansa Stark', 'activity': u'Development'},
{'duration': 2.17, 'project_id': 9, 'resource': u'Rickon Stark', 'activity': u'Development'},
{'duration': 1.03, 'project_id': 4, 'resource': u'Benjan Stark', 'activity': u'Design'},
{'duration': 1.77, 'project_id': 4, 'resource': u'Bran Stark', 'activity': u'Testing'},
{'duration': 1.17, 'project_id': 4, 'resource': u'Ned Stark', 'activity': u'Development'},
{'duration': 0.17, 'project_id': 9, 'resource': u'Jon Snow', 'activity': u'Support'},
{'duration': 1.77, 'project_id': 3, 'resource': u'catelyn stark', 'activity': u'Development'},
{'duration': 0.3, 'project_id': 9, 'resource': u'Jon Snow', 'activity': u'Support'},
{'duration': 0.45, 'project_id': 9, 'resource': u'Jon Snow', 'activity': u'Support'}]

All I need is to create a Table in python like

report_table = """<table>
.........
...........
..........
</table>"""

So the table format is attached,

enter image description here 1) It is possible to Bring in the desired format

2) Can we do summation operation inside dictionary data

1条回答
Summer. ? 凉城
2楼-- · 2019-03-22 04:47

IIUC Here is a solution using pandas:

import pandas as pd
dict_data = [{'duration': 0.7, 'project_id': 3, 'resource': u'Arya Stark', 'activity': u'Development'},
{'duration': 0.9, 'project_id': 4, 'resource': u'Ned Stark', 'activity': u'Development'},
{'duration': 2.88, 'project_id': 7, 'resource': u'Robb Stark', 'activity': u'Development'},
{'duration': 0.22, 'project_id': 9, 'resource': u'Jon Snow', 'activity': u'Support'},
{'duration': 0.3, 'project_id': 9, 'resource': u'Jon Snow', 'activity': u'Support'},
{'duration': 2.15, 'project_id': 3, 'resource': u'Arya Stark', 'activity': u'Practise'},
{'duration': 3.35, 'project_id': 4, 'resource': u'Sansa Stark', 'activity': u'Development'},
{'duration': 2.17, 'project_id': 9, 'resource': u'Rickon Stark', 'activity': u'Development'},
{'duration': 1.03, 'project_id': 4, 'resource': u'Benjan Stark', 'activity': u'Design'},
{'duration': 1.77, 'project_id': 4, 'resource': u'Bran Stark', 'activity': u'Testing'},
{'duration': 1.17, 'project_id': 4, 'resource': u'Ned Stark', 'activity': u'Development'},
{'duration': 0.17, 'project_id': 9, 'resource': u'Jon Snow', 'activity': u'Support'},
{'duration': 1.77, 'project_id': 3, 'resource': u'catelyn stark', 'activity': u'Development'},
{'duration': 0.3, 'project_id': 9, 'resource': u'Jon Snow', 'activity': u'Support'},
{'duration': 0.45, 'project_id': 9, 'resource': u'Jon Snow', 'activity': u'Support'}]

df = pd.DataFrame(dict_data)
dfg = df.groupby(['project_id','resource','activity']).sum()
dfg.to_html('result.html')

Will produce a html like this:

enter image description here

And another solution using pandas pivot_table with a different result:

import numpy as np

pvt = pd.pivot_table(df, values=['duration'],index=['project_id','resource'], columns=['activity'], aggfunc=np.sum,margins=True, fill_value=0)
pvt.to_html('result2.html')

enter image description here

Rearrange the total project wise: Rearrange the columns and index to get a desired rusult.

import numpy as np
pvt = pd.pivot_table(df, values=['duration'],index=['resource','activity'], columns=['project_id'], aggfunc=np.sum,margins=True, fill_value=0)

enter image description here

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