When I try to get my keyChain value, it return a string containing:
Optional("[thing in the KeyChain]")
so, I tried to remove "Optional" by using a loop:
var str = KeychainService.loadToken()
for(var i = 0; i < 9 ; i++)
{
str[i] = ""
}
But i get a error: NSString does not have a member named 'subscript'
The KeychainService class:
import Foundation
import Security
let serviceIdentifier = "MySerivice"
let userAccount = "authenticatedUser"
let accessGroup = "MySerivice"
// Arguments for the keychain queries
let kSecClassValue = kSecClass.takeRetainedValue() as NSString
let kSecAttrAccountValue = kSecAttrAccount.takeRetainedValue() as NSString
let kSecValueDataValue = kSecValueData.takeRetainedValue() as NSString
let kSecClassGenericPasswordValue = kSecClassGenericPassword.takeRetainedValue() as NSString
let kSecAttrServiceValue = kSecAttrService.takeRetainedValue() as NSString
let kSecMatchLimitValue = kSecMatchLimit.takeRetainedValue() as NSString
let kSecReturnDataValue = kSecReturnData.takeRetainedValue() as NSString
let kSecMatchLimitOneValue = kSecMatchLimitOne.takeRetainedValue() as NSString
class KeychainService: NSObject {
/**
* Exposed methods to perform queries.
* Note: feel free to play around with the arguments
* for these if you want to be able to customise the
* service identifier, user accounts, access groups, etc.
*/
internal class func saveToken(token: NSString) {
self.save(serviceIdentifier, data: token)
}
internal class func loadToken() -> NSString? {
var token = self.load(serviceIdentifier)
return token
}
/**
* Internal methods for querying the keychain.
*/
private class func save(service: NSString, data: NSString) {
var dataFromString: NSData = data.dataUsingEncoding(NSUTF8StringEncoding, allowLossyConversion: false)
// Instantiate a new default keychain query
var keychainQuery: NSMutableDictionary = NSMutableDictionary(objects: [kSecClassGenericPasswordValue, service, userAccount, dataFromString], forKeys: [kSecClassValue, kSecAttrServiceValue, kSecAttrAccountValue, kSecValueDataValue])
// Delete any existing items
SecItemDelete(keychainQuery as CFDictionaryRef)
// Add the new keychain item
var status: OSStatus = SecItemAdd(keychainQuery as CFDictionaryRef, nil)
}
private class func load(service: NSString) -> String? {
// Instantiate a new default keychain query
// Tell the query to return a result
// Limit our results to one item
var keychainQuery: NSMutableDictionary = NSMutableDictionary(objects: [kSecClassGenericPasswordValue, service, userAccount, kCFBooleanTrue, kSecMatchLimitOneValue], forKeys: [kSecClassValue, kSecAttrServiceValue, kSecAttrAccountValue, kSecReturnDataValue, kSecMatchLimitValue])
var dataTypeRef :Unmanaged<AnyObject>?
// Search for the keychain items
let status: OSStatus = SecItemCopyMatching(keychainQuery, &dataTypeRef)
let opaque = dataTypeRef?.toOpaque()
var contentsOfKeychain: String?
if let op = opaque? {
let retrievedData = Unmanaged<NSData>.fromOpaque(op).takeUnretainedValue()
// Convert the data retrieved from the keychain into a string
contentsOfKeychain = NSString(data: retrievedData, encoding: NSUTF8StringEncoding)
} else {
println("Nothing was retrieved from the keychain. Status code \(status)")
}
return contentsOfKeychain
}
}
I just wan't to remove the Optional thing around the str Or is there a better way to do that?
I have take this code from:
http://matthewpalmer.net/blog/2014/06/21/example-ios-keychain-swift-save-query/
You can use the Swift wrapper over the Keychain C API, and avoid the above problems altogether. https://github.com/deniskr/KeychainSwiftAPI
You actually don't even need to do anything. The "Optional" string isn't in the actual data. That is just something Swift seems to place on the output on the console when it is an optional value that isn't unwrapped. IE The data itself doesn't contain the string Optional.
Still, good to unwrap it if you know it contains data.
Here is a Swift 2 example implementation:
Output:
You get the
Optional("")
because the optional value is not unwrapped. You need to put a!
after the object and you won't get theOptional("")
bit any more. I would show you the code but you haven't shown us theprint()
statement. I made some sample ones below that I think would replicate the problem, though I haven't tried them.Im hoping this answers your question or at least points you in the right direction, just ask if you need more information or a better example.
You will get the Optional("") because the optional value is not unwrapped and if you want to unwrap the optional value to get the string value, do