How would I do MySQL count(*) in Doctrine2?

2019-03-18 04:05发布

I have the following Doctrine2 query:

$qb = $em->createQueryBuilder()
      ->select('t.tag_text, COUNT(*) as num_tags')
      ->from('CompanyWebsiteBundle:Tag2Post', 't2p')
      ->innerJoin('t2p.tags', 't')
      ->groupBy('t.tag_text')
;
$tags = $qb->getQuery()->getResult();

When run I get the following error:

[Semantical Error] line 0, col 21 near '*) as num_tags': Error: '*' is not defined. 

How would I do MySQL count(*) in Doctrine2?

3条回答
欢心
2楼-- · 2019-03-18 04:45

You're trying to do it in DQL not "in Doctrine 2".

You need to specify which field (note, I don't use the term column) you want to count, this is because you are using an ORM, and need to think in OOP way.

$qb = $em->createQueryBuilder()
      ->select('t.tag_text, COUNT(t.tag_text) as num_tags')
      ->from('CompanyWebsiteBundle:Tag2Post', 't2p')
      ->innerJoin('t2p.tags', 't')
      ->groupBy('t.tag_text')
;
$tags = $qb->getQuery()->getResult();

However, if you require performance, you may want to use a NativeQuery since your result is a simple scalar not an object.

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beautiful°
3楼-- · 2019-03-18 04:45

You should be able to do it just like this (building the query as a string):

$query = $em->createQuery('SELECT COUNT(u.id) FROM Entities\User u');
$count = $query->getSingleScalarResult();
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姐就是有狂的资本
4楼-- · 2019-03-18 04:57

As $query->getSingleScalarResult() expects at least one result hence throws a no result exception if there are not result found so use try catch block

try{
   $query->getSingleScalarResult();
}
catch(\Doctrine\ORM\NoResultException $e) {
        /*Your stuffs..*/
}
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