python get time stamp on file in mm/dd/yyyy format

2019-03-17 23:09发布

I'm trying to get the datestamp on the file in mm/dd/yyyy format

time.ctime(os.path.getmtime(file))

gives me detailed time stamp Fri Jun 07 16:54:31 2013

How can I display the output as 06/07/2013

3条回答
Root(大扎)
2楼-- · 2019-03-17 23:18

You want to use time.strftime() to format the timestamp; convert it to a time tuple first using either time.gmtime() or time.localtime():

time.strftime('%m/%d/%Y', time.gmtime(os.path.getmtime(file)))
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Melony?
3楼-- · 2019-03-17 23:27

You can create the datetime object using the ctime str like you mention and then format it back to a string of any format.

str1 = time.ctime(os.path.getmtime(file)) # Fri Jun 07 16:54:31 2013
datetime_object = datetime.strptime(str1, '%a %b %d %H:%M:%S %Y')
datetime_object.strftime("%m/%d/%Y") # 06/07/2013

This way you don't have to deal with timezones + absolute timestamp from the Epoch

Credit: Converting string into datetime

Linking: How to get file creation & modification date/times in Python?

http://strftime.org/

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▲ chillily
4楼-- · 2019-03-17 23:36
from datetime import datetime
from os.path import getmtime

datetime.fromtimestamp(getmtime(file)).strftime('%m/%d/%Y')
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