How to list only the file names in HDFS

Question

I would like to know is there any command/expression to get only the file name in hadoop. I need to fetch only the name of file, when I do hadoop fs -ls it prints the whole path.

I tried below but just wondering if some better way to do it.

hadoop fs -ls <HDFS_DIR>|cut -d ' ' -f17 

Answer 1

Use the basename command, which strips any prefix ending in '/' from the string.

basename $(hadoop fs -ls)

Answer 2

The Below Command return only the File names in the Directory. Awk Splits the list by '/' and prints last field which would be the File name.

hdfs dfs -ls /<folder> | awk -F'/' '{print $NF}'

Answer 3

The following command will return filenames only:

hdfs dfs -stat "%n" my/path/*

Answer 4

 hadoop fs -ls  -C  /path/* | xargs -n 1 basename

Answer 5

I hope this helps someone - with version 2.8.x+ (available in 3 as well) -

hadoop fs -ls  -C  /paths/

Answer 6

It seems hadoop ls does not support any options to output just the filenames, or even just the last column.

If you want get the last column reliably, you should first convert the whitespace to a single space, so that you can then address the last column:

hadoop fs -ls | sed '1d;s/  */ /g' | cut -d\  -f8

This will get you just the last column but files with the whole path. If you want just filenames, you can use basename as @rojomoke suggests:

hadoop fs -ls | sed '1d;s/  */ /g' | cut -d\  -f8 | xargs -n 1 basename

I also filtered out the first line that says Found ?x items

Note: beware that, as @felix-frank notes in the comments, that the above command will not correctly preserve file names with multiple consecutive spaces. Hence a more correct solution proposed by Felix:

hadoop fs -ls /tmp | sed 1d | perl -wlne'print +(split " ",$_,8)[7]'