We have a point (x,y) and a set of some other points (xi,yi). How can we determine which of (xi,yi) are within a circle with center (x,y) and radius r (a given number)?
相关问题
- add a circle at the edge of arc android?
- Animating radius growth/shrink of a circle on goog
- Slicing a circle in equal segments, Python
- Find point on Circle on Android
- Use X,Y coordinates to plot points inside a circle
相关文章
- 的JavaScript函数返回X,两个圆之间的交叉点ÿ?(A JavaScript function
- 如何画一个体面的在Java中寻找圈子如何画一个体面的在Java中寻找圈子(How to draw a
- 检测OpenCV的半圆检测OpenCV的半圆(Detect semi-circle in openc
- add a circle at the edge of arc android?
- Animating radius growth/shrink of a circle on goog
- Slicing a circle in equal segments, Python
- Find point on Circle on Android
- Use X,Y coordinates to plot points inside a circle
If (xi - x)^2 + (yi - y)^2 is less than d^2, it's inside. If it equals d^2, it's on the circle. If it's greater than d^2, it's outside.
If sqrt((xi-x)^2 + (yi-y)^2) <= d
I had the same problem to solve inside a plsql procedure. The solution above are completely right and I did the same. But it compromised the performance of my plsql program drastically. Instead of that circle calculation, I used a square. Because it can be done without doing such calculation and in the sql statement itself. It improved the query performance by more than 10x
Simple way.
Compute the distance from the point to the center of the circle. If less than radius , then its within the circle.