Regex to modify Google Drive shared file URL

Question

I'm trying to create a script to convert a regular google drive share URL to a direct download URL. The raw URL looks like this:

https://drive.google.com/file/d/FILE_ID/edit?usp=sharing

and needs to be converted to look like this:

https://drive.google.com/uc?export=download&id=FILE_ID

So I'm trying to make my regex, which I'm not very experienced with, to grab the needed text to be deleted/changed. I'm using RegExr to try to create it, but I only get as far as

/file/d/

I've tried a negative lookahead, but it doesn't seem to work. Any suggestions?

Answer 1

UPDATED ON 23 March 2017

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For PHP:

$link = preg_replace('%https://drive\.google\.com/file/d/(.*?)/.*?\?usp=sharing%', 'https://drive.google.com/uc?export=download&id=$1', $link);

For Python:

result = re.sub(r"https://drive\.google\.com/file/d/(.*?)/.*?\?usp=sharing", r"https://drive.google.com/uc?export=download&id=\1", url)

For Perl:

$subject =~ s!https://drive\.google\.com/file/d/(.*?)/.*?\?usp=sharing!https://drive.google.com/uc?export=download&id=$1!g;

For Java:

String resultString = subjectString.replaceAll("https://drive\\.google\\.com/file/d/(.*?)/.*?\\?usp=sharing", "https://drive.google.com/uc?export=download&id=$1");

For Ruby:

result = subject.gsub(/https:\/\/drive\.google\.com\/file\/d\/(.*?)\/.*?\?usp=sharing/, 'https://drive.google.com/uc?export=download&id=\1')

For C#:

resultString = Regex.Replace(subjectString, @"https://drive\.google\.com/file/d/(.*?)/.*?\?usp=sharing", "https://drive.google.com/uc?export=download&id=$1");

For R Language:

~gsub("https://drive\\.google\\.com/file/d/(.*?)/.*?\\?usp=sharing", "https://drive.google.com/uc?export=download&id=\\1", subject, perl=TRUE);

For Javascript:

result = subject.replace(/https:\/\/drive\.google\.com\/file\/d\/(.*?)\/.*?\?usp=sharing/g, "https://drive.google.com/uc?export=download&id=$1");

For TCL:

regsub -linestop -all {https://drive\.google\.com/file/d/(.*?)/.*?\?usp=sharing} $subject "https://drive.google.com/uc?export=download\\&id=\\1" result

for Oracle:

result := REGEXP_REPLACE(subject, 'https://drive\.google\.com/file/d/(.*)/.*?\?usp=sharing', 'https://drive.google.com/uc?export=download&id=\1', 1, 0, 'c');

For C++:

wxString ;
wxRegEx regexObj(_T("(?p)\\Ahttps://drive\\.google\\.com/file/d/(.*?)/.*?\\?usp=sharing"), wxRE_ADVANCED);
regexObj.ReplaceAll(&subjectString, _T("https://drive.google.com/uc?export=download\\&id=\\1"));

For Groovy:

Matcher regexMatcher = subjectString =~ /https:\/\/drive\.google\.com\/file\/d\/(.*?)\/.*?\?usp=sharing/
String resultString = regexMatcher.replaceAll('https://drive.google.com/uc?export=download&id=$1');

For PostgreSQL:

SELECT REGEXP_REPLACE(mycolumn, $$(?p)https://drive\.google\.com/file/d/(.*?)/.*?\?usp=sharing$$, $$https://drive.google.com/uc?export=download&id=\1$$, 'g') FROM mytable;

For VisualBasic.NET:

Dim RegexObj As New Regex("https://drive\.google\.com/file/d/(.*?)/.*?\?usp=sharing")
ResultString = RegexObj.Replace(SubjectString, "https://drive.google.com/uc?export=download&id=$1")

For Delphi XE:

Dim RegexObj As New Regex("https://drive\.google\.com/file/d/(.*?)/.*?\?usp=sharing")
ResultString = RegexObj.Replace(SubjectString, "https://drive.google.com/uc?export=download&id=$1")

For PowerShell:

$regex = [regex] 'https://drive\.google\.com/file/d/(.*?)/.*?\?usp=sharing'
$result = $regex.Replace($subject, 'https://drive.google.com/uc?export=download&id=$1')

For Xpath:

fn:replace($input, "https://drive\.google\.com/file/d/(.*?)/.*?\?usp=sharing", "https://drive.google.com/uc?export=download&id=$1")

For VBscript:

Dim myRegExp, ResultString
Set myRegExp = New RegExp
myRegExp.Global = True
myRegExp.Pattern = "https://drive\.google\.com/file/d/(.*?)/.*?\?usp=sharing"
ResultString = myRegExp.Replace(SubjectString, "https://drive.google.com/uc?export=download&id=$1")

If you need a different language just let me know! :)

Answer 2

This works in PCRE, in regex101:

• Find what: ^(https:\/\/drive\.google\.com\/)file\/d\/([^\/]+)\/.*$
• Replace with: $1uc?export=download&id=$2
• Try it: http://regex101.com/r/dX1zD2

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Please consider bookmarking the Stack Overflow Regular Expressions FAQ for future reference.

Answer 3

You don't need regex for that you can complete the url transformation with 2 chained string replace. See for example this (in Java) :

String url="https://drive.google.com/file/d/FILE_ID/edit?usp=sharing";
url = url.replace("/file/d/", "/uc?export=download&id=").replace("/edit?usp=sharing", "");
System.out.print(url); 

==> The output:

https://drive.google.com/uc?export=download&id=FILE_ID