RxJs: poll until interval done or correct data rec

Question

How do i execute the following scenario in the browser with RxJs:

• submit data to queue for processing
• get back the job id
• poll another endpoint every 1s until result is available or 60seconds have passed(then fail)

Intermediate solution that i've come up with:

 Rx.Observable
    .fromPromise(submitJobToQueue(jobData))
    .flatMap(jobQueueData => 
      Rx.Observable
            .interval(1000)
            .delay(5000)
            .map(_ => jobQueueData.jobId)
            .take(55)
    )
    .flatMap(jobId => Rx.Observable.fromPromise(pollQueueForResult(jobId)))
    .filter(result => result.completed)
    .subscribe(
      result => console.log('Result', result),
      error =>  console.log('Error', error)
    );

1. Is there a way without intermediate variables to stop the timer once the data arrives or error occurs? I now i could introduce new observable and then use takeUntil
2. Is flatMap usage here semantically correct? Maybe this whole thing should be rewritten and not chained with flatMap ?

Answer 1

Not your question, but I needed the same functionality

import { takeWhileInclusive } from 'rxjs-take-while-inclusive'
import { of, interval, race, throwError } from 'rxjs'
import { catchError, timeout, mergeMap, delay, switchMapTo } from 'rxjs/operators'

const defaultMaxWaitTimeMilliseconds = 5 * 1000

function isAsyncThingSatisfied(result) {
  return true
}

export function doAsyncThingSeveralTimesWithTimeout(
  doAsyncThingReturnsPromise,
  maxWaitTimeMilliseconds = defaultMaxWaitTimeMilliseconds,
  checkEveryMilliseconds = 500,
) {
  const subject$ = race(
    interval(checkEveryMilliseconds).pipe(
      mergeMap(() => doAsyncThingReturnsPromise()),
      takeWhileInclusive(result => isAsyncThingSatisfied(result)),
    ),
    of(null).pipe(
      delay(maxWaitTimeMilliseconds),
      switchMapTo(throwError('doAsyncThingSeveralTimesWithTimeout timeout'))
    )
  )

  return subject$.toPromise(Promise) // will return first result satistieble result of doAsyncThingReturnsPromise or throw error on timeout
}

Example

// mailhogWaitForNEmails
import { takeWhileInclusive } from 'rxjs-take-while-inclusive'
import { of, interval, race, throwError } from 'rxjs'
import { catchError, timeout, mergeMap, delay, switchMap } from 'rxjs/operators'

const defaultMaxWaitTimeMilliseconds = 5 * 1000

export function mailhogWaitForNEmails(
  mailhogClient,
  number,
  maxWaitTimeMilliseconds = defaultMaxWaitTimeMilliseconds,
  checkEveryMilliseconds = 500,
) {
  let tries = 0

  const mails$ = race(
    interval(checkEveryMilliseconds).pipe(
      mergeMap(() => mailhogClient.getAll()),
      takeWhileInclusive(mails => {
        tries += 1
        return mails.total < number
      }),
    ),
    of(null).pipe(
      delay(maxWaitTimeMilliseconds),
      switchMap(() => throwError(`mailhogWaitForNEmails timeout after ${tries} tries`))
    )
  )

  // toPromise returns promise which contains the last value from the Observable sequence.
  // If the Observable sequence is in error, then the Promise will be in the rejected stage.
  // If the sequence is empty, the Promise will not resolve.
  return mails$.toPromise(Promise)
}

// mailhogWaitForEmailAndClean
import { mailhogWaitForNEmails } from './mailhogWaitForNEmails'

export async function mailhogWaitForEmailAndClean(mailhogClient) {
  const mails = await mailhogWaitForNEmails(mailhogClient, 1)

  if (mails.count !== 1) {
    throw new Error(
      `Expected to receive 1 email, but received ${mails.count} emails`,
    )
  }

  await mailhogClient.deleteAll()

  return mails.items[0]
}

Answer 2

Starting from the top, you've got a promise that you turn into an observable. Once this yields a value, you want make a call once per second until you receive a certain response (success) or until a certain amount of time has passed. We can map each part of this explanation to an Rx method:

"Once this yields a value" = map/flatMap (flatMap in this case because what comes next will also be observables, and we need to flatten them out)

"once per second" = interval

"receive a certain response" = filter

"or" = amb

"certain amount of time has passed" = timer

From there, we can piece it together like so:

Rx.Observable
  .fromPromise(submitJobToQueue(jobData))
  .flatMap(jobQueueData =>
    Rx.Observable.interval(1000)
      .flatMap(() => pollQueueForResult(jobQueueData.jobId))
      .filter(x => x.completed)
      .take(1)
      .map(() => 'Completed')
      .amb(
        Rx.Observable.timer(60000)
          .flatMap(() => Rx.Observable.throw(new Error('Timeout')))
      )
  )
  .subscribe(
    x => console.log('Result', x),
    x => console.log('Error', x)
  )
;

Once we've got our initial result, we project that into a race between two observables, one that will yield a value when it receives a successful response, and one that will yield a value when a certain amount of time has passed. The second flatMap there is because .throw isn't present on observable instances, and the method on Rx.Observable returns an observable which also needs to be flattened out.

It turns out that the amb / timer combo can actually be replaced by timeout, like so:

Rx.Observable
  .fromPromise(submitJobToQueue(jobData))
  .flatMap(jobQueueData =>
    Rx.Observable.interval(1000)
      .flatMap(() => pollQueueForResult(jobQueueData.jobId))
      .filter(x => x.completed)
      .take(1)
      .map(() => 'Completed')
      .timeout(60000, Rx.Observable.throw(new Error('Timeout')))
  )
  .subscribe(
    x => console.log('Result', x),
    x => console.log('Error', x)
  )
;

I omitted the .delay you had in your sample as it wasn't described in your desired logic, but it could be fitted trivially to this solution.

So, to directly answer your questions:

1. In the code above there is no need to manually stop anything, as the interval will be disposed of the moment the subscriber count drops to zero, which will occur either when the take(1) or amb / timeout completes.
2. Yes, both usages in your original were valid, as in both cases you were projecting each element of an observable into a new observable, and wanting to flatten the resultant observable of observables out into a regular observable.

Here's the jsbin I threw together to test the solution (you can tweak the value returned in pollQueueForResult to obtain the desired success/timeout; times have been divided by 10 for the sake of quick testing).

Answer 3

A small optimization to the excellent answer from @matt-burnell. You can replace the filter and take operators with the first operator as follows

Rx.Observable
  .fromPromise(submitJobToQueue(jobData))
  .flatMap(jobQueueData =>
    Rx.Observable.interval(1000)
      .flatMap(() => pollQueueForResult(jobQueueData.jobId))
      .first(x => x.completed)
      .map(() => 'Completed')
      .timeout(60000, Rx.Observable.throw(new Error('Timeout')))

  )
  .subscribe(
    x => console.log('Result', x),
    x => console.log('Error', x)
  );

Also, for people that may not know, the flatMap operator is an alias for mergeMap in RxJS 5.0.