Qt get children from layout

Question

I try to hide all widgets in layout. But looks like findChildren doesn't work for layout.

Here's my sample code:

QLayout * layout = widget -> findChild<QLayout *> (layoutName);
QList<QWidget *> list = layout -> findChildren<QWidget *> ();

cout << list.size() << endl;

size is 0, but inside this layout I have a few widgets. But the same code works fine if I try to get widgets from parent widget.

How I can get them from appropriate layout?

Answer 1

You can simply iterate over the layout's items, using itemAt(), then test whether the item is a widget:

for (int i = 0; i < gridLayout->count(); ++i)
{
  QWidget *widget = gridLayout->itemAt(i)->widget();
  if (widget != NULL)
  {
    widget->setVisible(false);
  }
  else
  {
    // You may want to recurse, or perform different actions on layouts.
    // See gridLayout->itemAt(i)->layout()
  }
}

Answer 2

Responding to an old post, but I wanted a simple way to disable all widgets contained in a layout or any child-layout. This worked for my purposes:

void setEnabledWidgetsInLayout(QLayout *layout, bool enabled)
{
   if (layout == NULL)
      return;

   QWidget *pw = layout->parentWidget();
   if (pw == NULL)
      return;

   foreach(QWidget *w, pw->findChildren<QWidget*>())
   {
      if (isChildWidgetOfAnyLayout(layout,w))
         w->setEnabled(enabled);
   }
}

bool isChildWidgetOfAnyLayout(QLayout *layout, QWidget *widget)
{
   if (layout == NULL or widget == NULL)
      return false;

   if (layout->indexOf(widget) >= 0)
      return true;

   foreach(QObject *o, layout->children())
   {
      if (isChildWidgetOfAnyLayout((QLayout*)o,widget))
         return true;
   }

   return false;
}

Answer 3

It's very late but if anyone finds here like me, here is my solution: I tried @braggPeaks answer(it's same as @Frank Osterfeld answer) but it failed. Then I modified like this and it works like a charm. (I have no idea why it works, because my layout has no null items but still I have to check if it has.)

for (int i = 0; i < this->layout->count(); ++i) {
    QWidget *w = this->layout->itemAt(i)->widget();
    if(w != NULL)
        w->setVisible(false);
}

Answer 4

The layout does not "inject" itself in the parent-child tree, so the widgets stay (direct) children of their parent widget.

You could use QLayout::count() and QLayout::itemAt() instead.

Answer 5

Did you try children() method instead of findChildren() ? Maybe you are getting a 'bad' layout from widget -> findChild<QLayout *> (layoutName) method. Try to find children right after creating the layout - so you are sure the layout is correct. Doing so you will be able do determine what function works wrong.

Answer 6

Since layout is not part of widget hierarchy, the widget has to be queried from parent but then indexOf can be used to see if it belongs and its location

  QLayout * top_l= layout(); // The parent widgets layout
   // Find your layout that you want to search inside
   QHBoxLayout * hbox = top_l->findChild<QHBoxLayout*>(QString("horizontalLayout_2"));
    if (hbox != 0) {
        std::cout << "Found horizontalLayout_2!"<<std::endl;
        QPushButton * st = findChild<QPushButton*>(QString("startButton"));

        if (st != 0) {
            std::cout << "Found startButton in top level widget"<<std::endl;
            int idx = hbox->indexOf(st);
            if (idx >=0) {
                std::cout << "Found startButton in hbox layout at location : "
                          <<idx<<std::endl;
            }
        }
    };