I am using 7z command line executable to zip files, but I see that while adding to an archive the path of the files is preserved in the archive.
So if I do
7z a -tzip myzip.zip dir1\dir2\*
the archive myzip.zip will contain the path dir1\dir2. I do not want this, rather I want only the files to be added to the zip file without the paths being preserved. I searched quite a bit but do not seem to find any way of doing this, maybe I am missing something obvious?
Thanks
Just add a dot before the path, i.e.
7z a -tzip -r myzip.zip .\Relative\Dir\*
Give the full path. That should work. Not the relative path from the current location. For example, I give the below, where I want the files in the man5 folder to be archived.
The zip contained only the files, without the directories.
Then I gave only the relative path. It had the directories, inside the zip.
Tried with Linux (Ubuntu 12.04). Not sure whether that differs from Windows.
I discovered a way to do this by using a relative path:
%CD% is how you get the current path in a Windows batch file, but it also works from the command line. More info about Capturing the current directory from a batch file.
As explained in related question in 7-zip user FAQ, 7z stores paths relative to working directory, so you will need to first
cd
to desired top-level directory for archive and run 7-zip from here.If you run it from script and don't want to affect it with changed directory, use directory push/pop facilities available in your shell of choice or run cd+7-zip in spawned process to avoid affecting your entire script with changed directory. For example, using Windows' start that would be:
This worked for me
Consider folder structure like C:\Parent\SubFolders..... And you want to create parent.zip which will contain all files and folders C:\Parent without parent folder [i.e it will start from SubFolders.....]
This will create Parent.zip in C:\Parent