I am trying to predict fitted values over data containing NA
s, and based on a model generated by plm
. Here's some sample code:
require(plm)
test.data <- data.frame(id=c(1,1,2,2,3), time=c(1,2,1,2,1),
y=c(1,3,5,10,8), x=c(1, NA, 3,4,5))
model <- plm(y ~ x, data=test.data, index=c("id", "time"),
model="pooling", na.action=na.exclude)
yhat <- predict(model, test.data, na.action=na.pass)
test.data$yhat <- yhat
When I run the last line I get an error stating that the replacement has 4 rows while data has 5 rows.
I have no idea how to get predict return a vector of length 5...
If instead of running a plm
I run an lm
(as in the line below) I get the expected result.
model <- lm(y ~ x, data=test.data, na.action=na.exclude)
I think this is something that
predict.plm
ought to handle for you -- seems like an oversight on the package authors' part -- but you can use?napredict
to implement it for yourself: