Display a table/list data dynamically in MVC3/Razo

2019-03-13 01:10发布

I have a view page, users.cshtml. And I have a JsonResult action method, jsongetusers() that returns the list of users in json format.

On users.cshtml page load, I want to get the list of users, build a table and display it. What is the best way to implement this in ASP.Net MVC using Razor? I am pretty new to MVC3 and Razor. My initial thought was to loop through the json result and build a table using javascript/jquery and append it to the DOM. But I am guessing there must be a better way to do this?

Thanks.

5条回答
The star\"
2楼-- · 2019-03-13 01:44

You can do this easily with the KoGrid plugin for KnockoutJS.

<script type="text/javascript">
    $(function () {
        window.viewModel = {
            myObsArray: ko.observableArray([
                { id: 1, firstName: 'John', lastName: 'Doe', createdOn: '1/1/2012', birthday: '1/1/1977', salary: 40000 },
                { id: 1, firstName: 'Jane', lastName: 'Harper', createdOn: '1/2/2012', birthday: '2/1/1976', salary: 45000 },
                { id: 1, firstName: 'Jim', lastName: 'Carrey', createdOn: '1/3/2012', birthday: '3/1/1985', salary: 60000 },
                { id: 1, firstName: 'Joe', lastName: 'DiMaggio', createdOn: '1/4/2012', birthday: '4/1/1991', salary: 70000 }
            ])
        };

        ko.applyBindings(viewModel);
    });
</script>

<div data-bind="koGrid: { data: myObsArray }">

Sample

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贼婆χ
3楼-- · 2019-03-13 01:48

As Mystere Man suggested, getting just a view first and then again making an ajax call again to get the json result is unnecessary in this case. that is 2 calls to the server. I think you can directly return an HTML table of Users in the first call.

We will do this in this way. We will have a strongly typed view which will return the markup of list of users to the browser and this data is being supplied by an action method which we will invoke from our browser using an http request.

Have a ViewModel for the User

public class UserViewModel
{
  public int UserID { set;get;}
  public string FirstName { set;get;}
   //add remaining properties as per your requirement

}

and in your controller have a method to get a list of Users

public class UserController : Controller
{

   [HttpGet]
   public ActionResult List()
   {
     List<UserViewModel> objList=UserService.GetUsers();  // this method should returns list of  Users
     return View("users",objList)        
   }
}

Assuming that UserService.GetUsers() method will return a List of UserViewModel object which represents the list of usres in your datasource (Tables)

and in your users.cshtml ( which is under Views/User folder),

 @model List<UserViewModel>

 <table>

 @foreach(UserViewModel objUser in Model)
 {
   <tr>
      <td>@objUser.UserId.ToString()</td>
      <td>@objUser.FirstName</td>
   </tr>
 }
 </table>

All Set now you can access the url like yourdomain/User/List and it will give you a list of users in an HTML table.

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Evening l夕情丶
4楼-- · 2019-03-13 01:55

The normal way of doing it is:

  • You get the users from the database in controller.
  • You send a collection of users to the View
  • In the view to loop the list of users building the list.

You don't need a JsonResult or jQuery for this.

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迷人小祖宗
5楼-- · 2019-03-13 01:57

If you really need to go this way, then this is what you can do. There are probably better ways of doing it, but this is all that I have at the moment. I did no database calls, I just used dummy data. Please modify the code to fit in with your scenario. I used jQuery to populate the HTML table.

In my controller I have the an action method called GetEmployees that returns a JSON result with all the employees. This is where you would call your repository to return the users from a database:

public ActionResult GetEmployees()
{
     List<User> userList = new List<User>();

     User user1 = new User
     {
          Id = 1,
          FirstName = "First name 1",
          LastName = "Last name 1"
     };

     User user2 = new User
     {
          Id = 2,
          FirstName = "First name 2",
          LastName = "Last name 2"
     };

     userList.Add(user1);
     userList.Add(user2);

     return Json(userList, JsonRequestBehavior.AllowGet);
}

The User class looks like this:

public class User
{
     public int Id { get; set; }
     public string FirstName { get; set; }
     public string LastName { get; set; }
}

In your view you could have the following:

<div id="users">
     <table></table>
</div>

<script>

     $(document).ready(function () {

          var url = '/Home/GetEmployees';

          $.getJSON(url, function (data) {

               $.each(data, function (key, val) {

                    var user = '<tr><td>' + val.FirstName + '</td></tr>';

                    $('#users table').append(user);

               });
          });
     });

</script>

Regarding the code above: var url = '/Home/GetEmployees'; Home is the controller and GetEmployees is the action method that you defined above.

I hope this helps.

UPDATE:

This is how I would have done it..

I always create a view model class for a view. In this case I would have called it something like UserListViewModel:

public class UserListViewModel
{
     IEnumerable<User> Users { get; set; }
}

In my controller I would populate this Users list from a call to the database returning all the users:

public ActionResult List()
{
     UserListViewModel viewModel = new UserListViewModel
     {
          Users = userRepository.GetAllUsers()
     };

     return View(viewModel);
}

And in my view I would have the following:

<table>

@foreach(User user in Model.Users)
{
     <tr>
          <td>First Name:</td>
          <td>user.FirstName</td>
     </tr>
}

</table>
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走好不送
6楼-- · 2019-03-13 02:10

Add a View:

  1. Right-Click View Folder
  2. Click Add -> View
  3. Click Create a strongly-typed view
  4. Select your User class
  5. Select List as the Scaffold template

Add a controller and action method to call the view:

public ActionResult Index()
{
    var users = DataContext.GetUsers();
    return View(users);
}
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