How can I log current line, and stack info with Py

Question

I have logging function as follows.

logging.basicConfig(
    filename = fileName,
    format = "%(levelname) -10s %(asctime)s %(message)s",
    level = logging.DEBUG
)

def printinfo(string):
    if DEBUG:
        logging.info(string)

def printerror(string):
    if DEBUG:
        logging.error(string)
    print string

I need to login the line number, stack information. For example:

1: def hello():
2:    goodbye()
3:
4: def goodbye():
5:    printinfo()

---> Line 5: goodbye()/hello()

How can I do this with Python?

SOLVED

def printinfo(string):
    if DEBUG:
        frame = inspect.currentframe()
        stack_trace = traceback.format_stack(frame)
        logging.debug(stack_trace[:-1])
    if LOG:
        logging.info(string)

gives me this info which is exactly what I need.

DEBUG      2011-02-23 10:09:13,500 [
  '  File "/abc.py", line 553, in <module>\n    runUnitTest(COVERAGE, PROFILE)\n', 
  '  File "/abc.py", line 411, in runUnitTest\n    printinfo(string)\n']

Answer 1

import inspect
import traceback

def method():
   frame = inspect.currentframe()
   stack_trace = traceback.format_stack(frame)
   print ''.join(stack_trace)

Use stack_trace[:-1] to avoid including method/printinfo in the stack trace.

Answer 2

As of Python 3.2, this can be simplified to passing the stack_info=True flag to the logging calls. However, you'll need to use one of the above answers for any earlier version.