This may be a silly question, but it may shed some light on how joins work internally.
Let's say I have a large table L
and a small table S
(100K rows vs. 100 rows).
Would there be any difference in terms of speed between the following two options?:
OPTION 1: OPTION 2:
--------- ---------
SELECT * SELECT *
FROM L INNER JOIN S FROM S INNER JOIN L
ON L.id = S.id; ON L.id = S.id;
Notice that the only difference is the order in which the tables are joined.
I realize performance may vary between different SQL languages. If so, how would MySQL compare to Access?
No, the order does not matter.
Almost all RDBMS's (such MS Access, MySQL, SQL Server, ORACLE etc) use a cost based optimiser based upon column statistics. In most situations, the optimiser will choose a correct plan. In the example you gave, the order will not matter (provided statistics are up to date).
Ref.
Might be of interest: ACC: How to Optimize Queries in Microsoft Access 2.0, Microsoft Access 95, and Microsoft Access 97
Tony Toews's Microsoft Access Performance FAQ is worth reading.
I know Oracle's not on your list, but I think that most modern databases will behave that way.
You can see in the following execution plan, that there is no difference between the two statements.
It's a full access to each of the two tables (no index in my case), and then a
HASH JOIN
. Since you want everything from both tables, both tables need to be read and joined, the sequence does not have an impact.