I'm getting this error in Kotlin in this part:
class GitHubRepoAdapter(private val context: Context,
private val values: List<GithubRepo>) : ArrayAdapter<GithubRepo>(context, R.layout.list_item,
values) {
private val context: Context
in log it says:
Error:(14, 25) Accidental override: The following declarations have the same JVM signature (getContext()Landroid/content/Context;): fun (): Context fun getContext(): Context!
I'm not able to see what is causing the problem.
This happens because the Kotlin compiler tries to generate a getter for
val context
declared in your class primary constructor, namely a methodgetContext()
, but the base classArrayAdapter<T>
already has such a method.You can solve that by doing one of the following:
Change your class' constructor parameter not to be a
val
.In this case, the getter won't be generated, and the conflict will be gone.
This seems to be the preferrable solution in your case, because, even without redeclaration, there is already a synthetic property
context
inferred from the Java getter.Use the
@JvmName
annotation, apply it to thecontext
property getter:This will make the compiler generate the getter with another JVM name (the one specified in the annotation), thus avoiding the conflict, but making accessing it from Java less intuitive (especially since there will be two similar functions). In Kotlin, you will still be able to use the property with its original name
context
.In addition to the answer already given...
val
(orvar
) but change the name of the parameter to something that doesn't collide with the super class declaration.In a class declaration, the parameters in the constructor declarations are often more than just parameters. Using
val
orvar
, you are actually declaring property members (not just parameters). And along with the property members come automatic "getters" (and "setters" in the case ofvar
). The automatic getter, in the OP's case, is calledgetContext()
but the base class already has a getContext() (same signature).Most likely, the intent here was to just pass the
context
to the super, in which case, the other answer works best. But, in the case where a new property is desired, but the name chosen collides with a differently purposed member of the super, changing the name is the alternative.In short, changing the name applies when you do want a new member variable but a super class already exposes a different member by the same name.