Can I use an ASP.Net MVC Razor view to generate an

2019-03-12 03:52发布

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I'd like to make use of the Model Binding / Rendering capabilities of a Razor View to generate the HTML Body Content for an email I'm sending from my ASP.NET MVC Application.

Is there a way to render a view to a string instead of returning it as the ActionResult of a GET request?

To illustrate I'm looking for something that will do the following...

    public ActionResult SendEmail(int id)
    {
        EmailDetailsViewModel emailDetails = EmailDetailsViewModel().CreateEmailDetails(id);

        // THIS IS WHERE I NEED HELP...
        // I want to pass my ViewModel (emailDetails) to my View (EmailBodyRazorView) but instead of Rending that to the Response stream I want to capture the output and pass it to an email client.
        string htmlEmailBody = View("EmailBodyRazorView", emailDetails).ToString();

        // Once I have the htmlEmail body I'm good to go.  I've got a utilityt that will send the email for me.
        MyEmailUtility.SmtpSendEmail("stevejobs@apple.com", "Email Subject", htmlEmailBody);

        // Redirect another Action that will return a page to the user confirming the email was sent.
        return RedirectToAction("ConfirmationEmailWasSent");
    }

6条回答
傲
2楼-- · 2019-03-12 04:22

There is also Essential Mail: Razor package from NuGet. It is build over RazorEngine and provides simple interface for email rendering.

Email message template looks something like

@inherits Essential.Templating.Razor.Email.EmailTemplate
@using System.Net;
@{
    From = new MailAddress("example@email.com");
    Subject = "Email Subject";
}
@section Html 
{
   <html>
      <head>
          <title>Example</title>
      </head>
      <body>
          <h1>HTML part of the email</h1>
      </body>
   </html>
}
@section Text 
{
    Text part of the email.
}

The project is hosted on GitHub: https://github.com/smolyakoff/essential-templating/wiki/Email-Template-with-Razor

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Evening l夕情丶
3楼-- · 2019-03-12 04:28

You may checkout Postal for using views for sending emails.

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甜甜的少女心
4楼-- · 2019-03-12 04:28

Based on Ryan's answer, I did an extension method:

public static string RenderViewToString(this Controller source, string viewName)
{
  var viewEngineResult = ViewEngines.Engines.FindView(source.ControllerContext, viewName, null);
  using (StringWriter output = new StringWriter())
  {
    viewEngineResult.View.Render(new ViewContext(source.ControllerContext, viewEngineResult.View, source.ViewData, source.TempData, output), output);
    viewEngineResult.ViewEngine.ReleaseView(source.ControllerContext, viewEngineResult.View);
    return output.ToString();
  }
}

To call from inside a controller action (example usage):

  [AllowAnonymous]
  public class ErrorController : Controller
  {
    // GET: Error
    public ActionResult Index(System.Net.HttpStatusCode id)
    {
      Exception ex = null; // how do i get the exception that was thrown?
      if (!Debugger.IsAttached)
        Code.Email.Send(ConfigurationManager.AppSettings["BugReportEmailAddress"], 
          $"Bug Report: AgentPortal: {ex?.Message}", 
          this.RenderViewToString("BugReport"));
      Response.StatusCode = (int)id;
      return View();
    }
  }
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smile是对你的礼貌
5楼-- · 2019-03-12 04:29

Another one would be ActionMailer.Net: https://bitbucket.org/swaj/actionmailer.net/wiki/Home

From the website: An MVC 3-based port of the Rails ActionMailer library to ASP.NET MVC. The goal is to make it easy and relatively painless to send email from your application.

NuGet: Install-Package ActionMailer

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姐就是有狂的资本
7楼-- · 2019-03-12 04:37

If you just need to render the view into a string try something like this: 

public string ToHtml(string viewToRender, ViewDataDictionary viewData, ControllerContext controllerContext)
{
    var result = ViewEngines.Engines.FindView(controllerContext, viewToRender, null);

    StringWriter output;
    using (output = new StringWriter())
    {
        var viewContext = new ViewContext(controllerContext, result.View, viewData, controllerContext.Controller.TempData, output);
        result.View.Render(viewContext, output);
        result.ViewEngine.ReleaseView(controllerContext, result.View);
    }

    return output.ToString();
}

You'll need to pass in the name of the view and the ViewData and ControllerContext from your controller action.

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