Write code to convert given number into words (eg

Question

Write C/C++/Java code to convert given number into words.

eg:- Input: 1234

Output: One thousand two hundred thirty-four.

Input: 10

Output: Ten

Does it require a complete switch case for digits 0 to 10.

Adding "teen" after every number name (eg: 14: four "teen".) from 14 to 19.

And than adding "ty" and the digits name for a number in the range 20 to 99.

And so on.

I think there must be some far better approach for solving this.

C code is preferred.

Answer 1

import java.lang.*;
import java.io.*;
public class rupee
{
public static void main(String[] args)throws  IOException
{

int len=0,revnum=0,i,dup=0,j=0,k=0;
int gvalue;
 String[] ones={"one","Two","Three","Four","Five","Six","Seven","Eight","Nine","Eleven","Twelve","Thirteen","Fourteen","Fifteen","Sixteen","Seventeen","Eighteen","Nineteen",""};
String[] twos={"Ten","Twenty","Thirty","Fourty","fifty","Sixty","Seventy","eighty","Ninety",""};
System.out.println("\n Enter value");
InputStreamReader b=new InputStreamReader(System.in);
BufferedReader br=new BufferedReader(b);
gvalue=Integer.parseInt(br.readLine());
if(gvalue==10)

   System.out.println("Ten");

else if(gvalue==100)

  System.out.println("Hundred");

else if(gvalue==1000)
  System.out.println("Thousand");

dup=gvalue;
for(i=0;dup>0;i++)
{
  revnum=revnum*10+dup%10;
  len++;
  dup=dup/10;
}
while(j<len)
{
 if(gvalue<10)
 {
  System.out.println(ones[gvalue-1]);
 }
else if(gvalue>10&&gvalue<=19)
 {
  System.out.println(ones[gvalue-2]);
  break;
 }
else if(gvalue>19&&gvalue<100)
 {
   k=gvalue/10;
   gvalue=gvalue%10;
   System.out.println(twos[k-1]);
 }
else if(gvalue>100&&gvalue<1000)
 {
   k=gvalue/100;
   gvalue=gvalue%100;
   System.out.println(ones[k-1] +"Hundred");
 }
else if(gvalue>=1000&&gvalue<9999)
 {
   k=gvalue/1000;
   gvalue=gvalue%1000;
   System.out.println(ones[k-1]+"Thousand");
}
else if(gvalue>=11000&&gvalue<=19000)
 {
  k=gvalue/1000;
  gvalue=gvalue%1000;
  System.out.println(twos[k-2]+"Thousand");
 }      
else if(gvalue>=12000&&gvalue<100000)
{
 k=gvalue/10000;
     gvalue=gvalue%10000;
 System.out.println(ones[gvalue-1]);
}
else
{
 System.out.println("");
    }
j++;
}
}
}

Answer 2

Works for any number from 0 to 999999999.

This program gets a number from the user, divides it into three parts and stores them separately in an array. The three numbers are passed through a function that convert them into words. Then it adds "million" to the first part and "thousand" to the second part.

#include <iostream>
using namespace std;
int buffer = 0, partFunc[3] = {0, 0, 0}, part[3] = {0, 0, 0}, a, b, c, d;
long input, nFake = 0;
const char ones[][20] = {"",       "one",       "two",      "three",
                         "four",    "five",      "six",      "seven",
                         "eight",   "nine",      "ten",      "eleven",
                         "twelve",  "thirteen",  "fourteen", "fifteen",
                         "sixteen", "seventeen", "eighteen", "nineteen"};
const char tens[][20] = {"",     "ten",   "twenty",  "thirty", "forty",
                         "fifty", "sixty", "seventy", "eighty", "ninety"};
void convert(int funcVar);
int main() {
  cout << "Enter the number:";
  cin >> input;
  nFake = input;
  buffer = 0;
  while (nFake) {
    part[buffer] = nFake % 1000;
    nFake /= 1000;
    buffer++;
  }
  if (buffer == 0) {
    cout << "Zero.";
  } else if (buffer == 1) {
    convert(part[0]);
  } else if (buffer == 2) {
    convert(part[1]);
    cout << " thousand,";
    convert(part[0]);
  } else {
    convert(part[2]);
    cout << " million,";

    if (part[1]) {
      convert(part[1]);
      cout << " thousand,";
    } else {
      cout << "";
    }
    convert(part[0]);
  }
  system("pause");
  return (0);
}

void convert(int funcVar) {
  buffer = 0;
  if (funcVar >= 100) {
    a = funcVar / 100;
    b = funcVar % 100;
    if (b)
      cout << " " << ones[a] << " hundred and";
    else
      cout << " " << ones[a] << " hundred ";
    if (b < 20)
      cout << " " << ones[b];
    else {
      c = b / 10;
      cout << " " << tens[c];
      d = b % 10;
      cout << " " << ones[d];
    }
  } else {
    b = funcVar;
    if (b < 20)
      cout << ones[b];
    else {
      c = b / 10;
      cout << tens[c];
      d = b % 10;
      cout << " " << ones[d];
    }
  }
}