Getting the source behind clang's AST

Question

Given an AST object in clang, how can I get the code behind it? I tried editing the code in the tutorial, and added:

clang::SourceLocation _b = d->getLocStart(), _e = d->getLocEnd();
char *b = sourceManager->getCharacterData(_b),
      e = sourceManager->getCharacterData(_E);
llvm:errs() << std::string(b, e-b) << "\n";

but alas, it didn't print the whole typedef declaration, only about half of it! The same phenomena happened when printing Expr.

How can I print and see the whole original string constituting the declaration?

Answer 1

Elazar's method worked for me except when a macro was involved. The following correction resolved it:

std::string decl2str(clang::Decl *d) {
    clang::SourceLocation b(d->getLocStart()), _e(d->getLocEnd());
    if (b.isMacroID())
        b = sm->getSpellingLoc(b);
    if (e.isMacroID())
        e = sm->getSpellingLoc(e);
    clang::SourceLocation e(clang::Lexer::getLocForEndOfToken(_e, 0, *sm, lopt));
    return std::string(sm->getCharacterData(b),
        sm->getCharacterData(e)-sm->getCharacterData(b));
}

Answer 2

Use the Lexer module:

clang::SourceManager *sm;
clang::LangOptions lopt;

std::string decl2str(clang::Decl *d) {
    clang::SourceLocation b(d->getLocStart()), _e(d->getLocEnd());
    clang::SourceLocation e(clang::Lexer::getLocForEndOfToken(_e, 0, *sm, lopt));
    return std::string(sm->getCharacterData(b),
        sm->getCharacterData(e)-sm->getCharacterData(b));
}

Answer 3

The following code works for me.

std::string decl2str(clang::Decl *d, SourceManager &sm) {
    // (T, U) => "T,,"
    string text = Lexer::getSourceText(CharSourceRange::getTokenRange(d->getSourceRange()), sm, LangOptions(), 0);
    if (text.size() > 0 && (text.at(text.size()-1) == ',')) //the text can be ""
        return Lexer::getSourceText(CharSourceRange::getCharRange(d->getSourceRange()), sm, LangOptions(), 0);
    return text;
}