Flask: get current route

2019-03-09 15:47发布

In Flask, when I have several routes for the same function, how can I know which route is used at the moment?

For example:

@app.route("/antitop/")
@app.route("/top/")
@requires_auth
def show_top():
    ....

How can I know, that now I was called using /top/ or /antitop/?

UPDATE

I know about request_path I don't want use it, because the request can be rather complex, and I want repeat the routing logic in the function. I think that the solution with url_rule it the best one.

标签: python url flask
5条回答
【Aperson】
2楼-- · 2019-03-09 16:27

It seems to me that if you have a situation where it matters, you shouldn't be using the same function in the first place. Split it out into two separate handlers, which each call a common fiction for the shared code.

查看更多
\"骚年 ilove
3楼-- · 2019-03-09 16:28

If you want different behaviour to each route, the right thing to do is create two function handlers.

@app.route("/antitop/")
@requires_auth
def top():
    ...

@app.route("/top/")
@requires_auth
def anti_top():
    ...

In some cases, your structure makes sense. You can set values per route.

@app.route("/antitop/", defaults={'_route': 'antitop'})
@app.route("/top/", defaults={'_route': 'top'})
@requires_auth
def show_top(_route):
    # use _route here
    ...
查看更多
Animai°情兽
4楼-- · 2019-03-09 16:44

the most 'flasky' way to check which route triggered your view is, by request.url_rule.

from flask import request

rule = request.url_rule

if 'antitop' in rule.rule:
    # request by '/antitop'

elif 'top' in rule.rule:
    # request by '/top'
查看更多
趁早两清
5楼-- · 2019-03-09 16:44

Another option is to use endpoint variable:

@app.route("/api/v1/generate_data", methods=['POST'], endpoint='v1')
@app.route("/api/v2/generate_data", methods=['POST'], endpoint='v2')
def generate_data():
    version = request.endpoint
    return version
查看更多
地球回转人心会变
6楼-- · 2019-03-09 16:47

Simply use request.path.

from flask import request

...

@app.route("/antitop/")
@app.route("/top/")
@requires_auth
def show_top():
    ... request.path ...
查看更多
登录 后发表回答