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Can the default destructor be generated as a virtual destructor automatically?
If I define a base class but no default destructor, is there a default virtual destructor generated automatically?
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No. There is a cost associated with making a method virtual, and C++ has a philosophy of not making you pay for things that you don't explicitly state that you want to use. If a virtual destructor would have been generated automatically, you would have been paying the price automatically.
Why not just define an empty virtual destructor?