Shell script to copy files from one location to an

Question

I have a folder in my server which contains some files. These are automated that means everyday we get new files automatically which will overwrite the old ones. So want to take a back up for this data. How can i copy all these files in to a another folder by renaming the files with current date while copying.

ex : i have a folder named folder1 which contains 4 files. path for this folder is home/webapps/project1/folder1

1. aaa.csv
2. bbb.csv
3. ccc.csv
4. ddd.csv

now i want to copy all these four files in to a different folder named folder2. path for this folder is home/webapps/project1/folder2. while copying these files i want to rename each file and add the current date to the file. so my file names in folder2 should be..

1. aaa091012.csv
2. bbb091012.csv
3. ccc091012.csv
4. ddd091012.csv

I want to write a shell script for this. Please give me some idea or some sample scripts related to this.

Answer 1

cp --archive home/webapps/project1/folder1/{aaa,bbb,ccc,ffffd}.csv home/webapps/project1/folder2
rename 's/\.csv$/'$(date +%m%d%Y).csv'/' home/webapps/project1/folder2/{aaa,bbb,ccc,ffffd}.csv

Explanation:

• --archive ensures that the files are copied with the same ownership and permissions.
• foo{bar,baz} is expanded into foobar foobaz.
• rename is a commonly available program to do exactly this kind of substitution.

PS: don't use ls for this.

Answer 2

You could use a script like the below. You would just need to change the date options to match the format you wanted.

#!/bin/bash

for i in `ls -l /directroy`
do
cp $i /newDirectory/$i.`date +%m%d%Y`
done

Answer 3

There is a proper way to split the filename and the extension: Extract filename and extension in Bash

You can apply it like this:

date=$(date +"%m%d%y")
for FILE in folder1/*.csv
do
    bname=$(basename "$FILE")
    extension="${bname##*.}"
    filenamewoext="${bname%.*}"
    newfilename="${filenamewoext}${date}.${extension}
    cp folder1/${FILE} folder2/${newfilename}
done

Answer 4

path_src=./folder1
path_dst=./folder2
date=$(date +"%m%d%y")
for file_src in $path_src/*; do
  file_dst="$path_dst/$(basename $file_src | \
    sed "s/^\(.*\)\.\(.*\)/\1$date.\2/")"
  echo mv "$file_src" "$file_dst"
done

Answer 5

You can be used this step is very useful:

for i in `ls -l folder1 | grep -v total | awk '{print $ ( ? )}'`
do
   cd folder1
   cp $i folder2/$i.`date +%m%d%Y`
done

Answer 6

In bash, provided you files names have no spaces:

cd /home/webapps/project1/folder1
for f in *.csv
do 
   cp -v "$f" /home/webapps/project1/folder2/"${f%.csv}"$(date +%m%d%y).csv
done