Highlight text similar to grep, but don't filt

Question

This question already has an answer here:

• Colorized grep — viewing the entire file with highlighted matches 17 answers

When using grep, it will highlight any text in a line with a match to your regular expression.

What if I want this behaviour, but have grep print out all lines as well? I came up empty after a quick look through the grep man page.

Answer 1

You can use my highlight script from https://github.com/kepkin/dev-shell-essentials

It's better than grep cause you can highlight each match with it's own color.

$ command_here | highlight green "input" | highlight red "output"

Answer 2

If you want to print "all" lines, there is a simple working solution:

grep "test" -A 9999999 -B 9999999

• A => After
• B => Before

Answer 3

Use ack. Checkout its --passthru option here: ack. It has the added benefit of allowing full perl regular expressions.

$ ack --passthru 'pattern1' file_name

$ command_here | ack --passthru 'pattern1'

You can also do it using grep like this:

$ grep --color -E '^|pattern1|pattern2' file_name

$ command_here | grep --color -E '^|pattern1|pattern2'

This will match all lines and highlight the patterns. The ^ matches every start of line, but won't get printed/highlighted since it's not a character.

(Note that most of the setups will use --color by default. You may not need that flag).

Answer 4

EDIT:

This works with OS X Mountain Lion's grep:

grep --color -E 'pattern1|pattern2|$'

This is better than '^|pattern1|pattern2' because the ^ part of the alternation matches at the beginning of the line whereas the $ matches at the end of the line. Some regular expression engines won't highlight pattern1 or pattern2 because ^ already matched and the engine is eager.

Something similar happens for 'pattern1|pattern2|' because the regex engine notices the empty alternation at the end of the pattern string matches the beginning of the subject string.

[1]: http://www.regular-expressions.info/engine.html

FIRST EDIT:

I ended up using perl:

perl -pe 's:pattern:\033[31;1m$&\033[30;0m:g'

This assumes you have an ANSI-compatible terminal.

ORIGINAL ANSWER:

If you're stuck with a strange grep, this might work:

grep -E --color=always -A500 -B500 'pattern1|pattern2' | grep -v '^--'

Adjust the numbers to get all the lines you want.

The second grep just removes extraneous -- lines inserted by the BSD-style grep on Mac OS X Mountain Lion, even when the context of consecutive matches overlap.

I thought GNU grep omitted the -- lines when context overlaps, but it's been awhile so maybe I remember wrong.

Answer 5

Since you want matches highlighted, this is probably for human consumption (as opposed to piping to another program for instance), so a nice solution would be to use:

less -p <your-pattern> <your-file>

And if you don't care about case sensitivity:

less -i -p <your-pattern> <your-file>

This also has the advantage of having pages, which is nice when having to go through a long output

Answer 6

You can do it using only grep by:

1. reading the file line by line
2. matching a pattern in each line and highlighting pattern by grep
3. if there is no match, echo the line as is

which gives you the following:

while read line ; do (echo $line | grep PATTERN) || echo $line  ; done < inputfile