How do I define the function in the importer so that it is visible inside imported? I tried this
importer.py
is
def build():
print "building"
build()
import imported
Whereby, imported.py
is simply
build()
Yet, this fails
building
Traceback (most recent call last):
File "C:\Users\valentin\Desktop\projects\maxim\miniGP\b01\evaluator\importer.py", line 6, in <module>
import imported
File "C:\Users\valentin\Desktop\projects\maxim\miniGP\b01\evaluator\imported.py", line 1, in <module>
build()
NameError: name 'build' is not defined
Update After I have got the response to make the circular import, so that import and imported depend on each other, I feel that I need to make clear that this is not always good. My purpose is to specify some common strategy in the imported module. It will use some user-defined functions, e.g. build
. User defines the necessary function(s) and calls the strategy. The point is that the shared strategy must not depend on specific user definitions. I believe that in place of import
, I need something like evaluate(imported.py)
, which I believe is a basic function in any script language, including Python. irc://freenode/python insists that I must use import
but I do not understand how.
Imports are not includes: they are idempotent and should always be at the top of a module.
There is no circularity; once
import foo
is seen, further instances ofimport foo
will not load the module again.You are getting the NameError because in the context of imported.py, there is no name
build
, it is known asimporter.build()
.I have no idea what you are trying to do with code as oddly structured as that.
importer.py
imported.py
Note that both importer.py and imported.py must be in same directory. I hope this solve your problem
I know that this is a blasphemy but the thing that allows to import a module without tying the imported with importer is easily available in Python as a script language. You can always evaluate a file with execfile