How can I remove the extension of a filename in a

2019-01-05 10:27发布

What's wrong with the following code?

name='$filename | cut -f1 -d'.''

As is, I get the literal string $filename | cut -f1 -d'.', but if I remove the quotes I don't get anything. Meanwhile typing

"test.exe" | cut -f1 -d'.'

in a shell gives me the output I want, test. I already know $filename has been assigned the right value. What I want to do is assign to a variable the filename without the extension.

9条回答
该账号已被封号
2楼-- · 2019-01-05 10:36

If your filename contains a dot (other than the one of the extension) then use this:

echo $filename | rev | cut -f 2- -d '.' | rev
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ら.Afraid
3楼-- · 2019-01-05 10:40
#!/bin/bash
file=/tmp/foo.bar.gz
echo $file ${file%.*}

outputs:

/tmp/foo.bar.gz /tmp/foo.bar

Note that only the last extension is removed.

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ゆ 、 Hurt°
4楼-- · 2019-01-05 10:47

Two problems with your code:

  1. You used a ' (tick) instead of a ` (back tick) to surround the commands that generate the string you want to store in the variable.
  2. You didn't "echo" the variable "$filename" to the pipe into the "cut" command.

I'd change your code to "name=`echo $filename | cut -f 1 -d '.' `", as shown below (again, notice the back ticks surrounding the name variable definition):

$> filename=foo.txt
$> echo $filename
foo.txt
$> name=`echo $filename | cut -f1 -d'.'`
$> echo $name
foo
$> 
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贪生不怕死
5楼-- · 2019-01-05 10:48

You should be using the command substitution syntax $(command) when you want to execute a command in script/command.

So your line would be

name=$(echo "$filename" | cut -f 1 -d '.')

Code explanation:

  1. echo get the value of the variable $filename and send it to standard output
  2. We then grab the output and pipe it to the cut command
  3. The cut will use the . as delimiter (also known as separator) for cutting the string into segments and by -f we select which segment we want to have in output
  4. Then the $() command substitution will get the output and return its value
  5. The returned value will be assigned to the variable named name

Note that this gives the portion of the variable up to the first period .:

$ filename=hello.world
$ echo "$filename" | cut -f 1 -d '.'
hello
$ filename=hello.hello.hello
$ echo "$filename" | cut -f 1 -d '.'
hello
$ filename=hello
$ echo "$filename" | cut -f 1 -d '.'
hello
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放荡不羁爱自由
6楼-- · 2019-01-05 10:48
file1=/tmp/main.one.two.sh
t=$(basename "$file1")                        # output is main.one.two.sh
name=$(echo "$file1" | sed -e 's/\.[^.]*$//') # output is /tmp/main.one.two
name=$(echo "$t" | sed -e 's/\.[^.]*$//')     # output is main.one.two

use whichever you want. Here I assume that last . (dot) followed by text is extension.

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看我几分像从前
7楼-- · 2019-01-05 10:51

You can also use parameter expansion:

$ filename=foo.txt
$ echo "${filename%.*}"
foo
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