I have situation where I believe I need to create a Deferred object with a "then" handler, but wait until the "then" handler has completed it's own promise before moving on.
The use case is a record object, and the above function is it's save method. The record object has an attribute called saveQueue, which is set to $.Deferred() on the record's instantiation. The resolve call on saveQueue was supposed to make sure the Deferred there is always executing every new handler attached to it as soon as it could. The idea being that you can call save several times on the record in short succession, but the calls will run one after another, and not overlap.
I am using a Deferred to enqueue Ajax calls, so that one does not run until the previous one call finished. However, from the same method, I want to return a Deferred that can be resolved/rejected by the jQuery Ajax object, like so:
record.saveQueue = $.Deferred();
self.save = function( record ){
var deferredAction = $.Deferred();
deferredAction.then(function() {
return $.post("/example_save_endpoint");
});
record.saveQueue.always(function(){
deferredAction.resolve();
}).resolve();
return deferredAction;
}
However, when I use this code, the deferredAction
promise always ends up resolved
, presumably because the #then handler is returning a "pending" (and thus non-rejecting) promise. Is there any way to force the Deferred to wait until the Ajax promise is complete before resolving/rejecting? Or is there another, better way to thread this needle?
I would probably choose not to do it this way, but a deferred/promise can indeed be used as a queuing device.
You need a slight(?) variation of what you already tried.
For explanation, see comments in code
Your idea might work, but
.resolve()
every time the method is called, instead it should be initialised only with a resolved promise.record.saveQueue
, it needs to be changed (overwritten) on every method call, to represent the end of the latest request.And we don't need any deferreds for that, as we can work with the promises that
$.post
returns.So use this: