Is it possible to use 'else' in a python l

Question

Here is the code I was trying to turn into a list comprehension:

table = ''
for index in xrange(256):
    if index in ords_to_keep:
        table += chr(index)
    else:
        table += replace_with

Is there a way to add the else statement to this comprehension?

table = ''.join(chr(index) for index in xrange(15) if index in ords_to_keep)

Answer 1

Yes, else can be used in Python inside a list comprehension with a Conditional Expression ("ternary operator"):

>>> [("A" if b=="e" else "c") for b in "comprehension"]
['c', 'c', 'c', 'c', 'c', 'A', 'c', 'A', 'c', 'c', 'c', 'c', 'c']

Here, the parentheses "()" are just to emphasize the conditional expression, they are not necessarily required (Operator precedence).

Additionaly, several expressions can be nested, resulting in more elses and harder to read code:

>>> ["A" if b=="e" else "d" if True else "x" for b in "comprehension"]
['d', 'd', 'd', 'd', 'd', 'A', 'd', 'A', 'd', 'd', 'd', 'd', 'd']
>>>

On a related note, a comprehension can also contain its own if condition(s) at the end:

>>> ["A" if b=="e" else "c" for b in "comprehension" if False]
[]
>>> ["A" if b=="e" else "c" for b in "comprehension" if "comprehension".index(b)%2]
['c', 'c', 'A', 'A', 'c', 'c']

Conditions? Yes, multiple ifs are possible, and actually multiple fors, too:

>>> [i for i in range(3) for _ in range(3)]
[0, 0, 0, 1, 1, 1, 2, 2, 2]
>>> [i for i in range(3) if i for _ in range(3) if _ if True if True]
[1, 1, 2, 2]

(The single underscore _ is a valid variable name (identifier) in Python, used here just to show it's not actually used. It has a special meaning in interactive mode)

Using this for an additional conditional expression is possible, but of no real use:

>>> [i for i in range(3)]
[0, 1, 2]
>>> [i for i in range(3) if i]
[1, 2]
>>> [i for i in range(3) if (True if i else False)]
[1, 2]

Comprehensions can also be nested to create "multi-dimensional" lists ("arrays"):

>>> [[i for j in range(i)] for i in range(3)]
[[], [1], [2, 2]]

---

Last but not least, a comprehension is not limited to creating a list, i.e. else and if can also be used the same way in a set comprehension:

>>> {i for i in "set comprehension"}
{'o', 'p', 'm', 'n', 'c', 'r', 'i', 't', 'h', 'e', 's', ' '}

and a dictionary comprehension:

>>> {k:v for k,v in [("key","value"), ("dict","comprehension")]}
{'key': 'value', 'dict': 'comprehension'}

The same syntax is also used for Generator Expressions:

>>> for g in ("a" if b else "c" for b in "generator"):
...     print(g, end="")
...
aaaaaaaaa>>>

which can be used to create a tuple (there is no tuple comprehension).

---

Further reading:

• The Python Tutorial on Data Structures
  • List Comprehensions
  • Sets
  • Dictionaries

Answer 2

Also, would I be right in concluding that a list comprehension is the most efficient way to do this?

Maybe. List comprehensions are not inherently computationally efficient. It is still running in linear time.

From my personal experience: I have significantly reduced computation time when dealing with large data sets by replacing list comprehensions (specifically nested ones) with for-loop/list-appending type structures you have above. In this application I doubt you will notice a difference.

Answer 3

Great answers, but just wanted to mention a gotcha that "pass" keyword will not work in the if/else part of the list-comprehension (as posted in the examples mentioned above).

#works
list1 = [10, 20, 30, 40, 50]
newlist2 = [x if x > 30 else x**2 for x in list1 ]
print(newlist2, type(newlist2))

#but this WONT work
list1 = [10, 20, 30, 40, 50]
newlist2 = [x if x > 30 else pass for x in list1 ]
print(newlist2, type(newlist2))

This is tried and tested on python 3.4. Error is as below:

newlist2 = [x if x > 30 else pass for x in list1 ]                                    
SyntaxError: invalid syntax

So, try to avoid pass-es in list comprehensions

Answer 4

To use the else in list comprehensions in python programming you can try out the below snippet. This would resolve your problem, the snippet is tested on python 2.7 and python 3.5.

obj = ["Even" if i%2==0 else "Odd" for i in range(10)]

Answer 5

The syntax a if b else c is a ternary operator in Python that evaluates to a if the condition b is true - otherwise, it evaluates to c. It can be used in comprehension statements:

>>> [a if a else 2 for a in [0,1,0,3]]
[2, 1, 2, 3]

So for your example,

table = ''.join(chr(index) if index in ords_to_keep else replace_with
                for index in xrange(15))

Answer 6

If you want an else you don't want to filter the list comprehension, you want it to iterate over every value. You can use true-value if cond else false-value as the statement instead, and remove the filter from the end:

table = ''.join(chr(index) if index in ords_to_keep else replace_with for index in xrange(15))