{var%20f='http://v.t.sina.com.cn/share/share.php?appkey=1515056452',u=z||d.location,p=['&url=',e(u),'&title=',e(t||d.title),'&source=',e(r),'&sourceUrl=',e(l),'&content=',c||'gb2312','&pic=',e(p||'')].join('');function%20a(){if(!window.open([f,p].join(''),'mb',['toolbar=0,status=0,resizable=1,width=440,height=430,left=',(s.width-440)/2,',top=',(s.height-430)/2].join('')))u.href=[f,p].join('');};if(/Firefox/.test(navigator.userAgent))setTimeout(a,0);else%20a();})(screen,document,encodeURIComponent,'','','https://www.manongdao.com/data/attach/logo/logo.png', '推荐 放我归山 的问题《in Jqgrid how to show dropdown value which was upd》','https://www.manongdao.com/q-441052.html','页面编码gb2312|utf-8默认gb2312'));){kind=link}
below is the code, in this the dropdown selected by the user is getting updated in database, but after refreshing the page i want to to display the value from database which was selected by user previously.now after refreshing the page the cell is blank.kindly help.
$qr="SELECT id,`emp_id`,`emp_name`, `att_date`, `emp_join_date`, `intime`,`outtime`,`Total_Hours`,`OT Hours`,`Status` FROM `db_emp_attendance` WHERE Status='Absent' and att_date='2017-04-01'";
$q = mysql_query($qr);
$rows = array();
while($r = mysql_fetch_assoc($q)) {
$rows[] = $r;
}
$json_data=json_encode($rows);
?>
<!DOCTYPE html>
<html lang="en">
<head>
<script type="text/ecmascript" src="jquery.min.js"></script>
<script type="text/ecmascript" src="jquery.jqGrid.min.js"></script>
<script type="text/ecmascript" src="grid.locale-en.js"></script>
<link rel="stylesheet" type="text/css" media="screen" href="jquery-ui.css"/>
<link rel="stylesheet" type="text/css" media="screen" href="ui.jqgrid.css"/>
<meta charset="utf-8" />
</head>
<body>
<table id="rowed5"></table>
<script type="text/javascript">
var lastsel2
jQuery("#rowed5").jqGrid({
datatype: "local",
height: 400,
autowidth: true,
colNames:['ID','Emp ID','Name', 'Join Date','Attendance Date', 'Time In','Time Out','Total Hours','OT Hours','Status','leave_type'],
colModel:[
{name:'id',index:'id', width:75,align:"center",key: true},
{name:'emp_id',index:'emp_id', width:75,align:"center"},
{name:'emp_name',index:'emp_name', width:150,align:"left"},
{name:'emp_join_date',index:'emp_join_date', width:150,align:"center"},
{name:'att_date',index:'att_date', width:100, align:"center"},
{name:'intime',index:'intime', width:80,align:"center"},
{name:'outtime',index:'outtime', width:80,align:"center"},
{name:'Total_Hours',index:'Total_Hours', width:80,align:"center"},
{name:'OT Hours',index:'OT Hours', width:80,align:"center"},
{name:'Status',index:'Status', width:150,align:"center"},
{name:'leave_type',index:'leave_type', width:150,
sortable:false,editable: true,
edittype: "select",
editoptions: {
value: "SickLeave:SickLeave;DayOff:DayOff;Vacation:Vacation"}
}
],
onSelectRow: function(id){
if(id && id!==lastsel2){
jQuery('#rowed5').jqGrid('restoreRow',lastsel2);
jQuery('#rowed5').jqGrid('editRow',id,true);
lastsel2=id;
}
},
editurl:'update.php',
cellEdit : true,
cellsubmit : 'remote',
cellurl : 'update.php',
caption: "Attendance"
});
var mydata2 =<?PHP echo $json_data;?>;
for(var i=0;i < mydata2.length;i++)
jQuery("#rowed5").jqGrid('addRowData',mydata2[i].id,mydata2[i]);
</script>
</body>
</html>
Free jqGrid 4.14.0 allows to generate the
editoptions.valueoreditoptions.valuebased on the all data of the grid. The setting in the column could looks likeIf you use the filter toolbar, then the only thing, which one have to do additionally is recreating the filter toolbar by calling
destroyFilterToolbarandfilterToolbarmethods. Editing have no such problems.The demo https://jsfiddle.net/OlegKi/yvbt6w54/1/, which I referenced in the README of the version 4.14.0, demonstrates the feature. Moreover, the demo shows how one can combine the feature with jQuery UI Autocomplete and select2.