I excited with this fiddle and I tried to create the same kind with reference to that fiddle. My modified sample is given in here and i'm trying to create a view as follows.
var distinctValues = data.getDistinctValues(2);
var viewColumns = [1];
var groupColumns = [];
// build column arrays for the view and grouping
for (var i = 0; i < distinctValues.length; i++) {
viewColumns.push({
type: 'number',
label: distinctValues[i],
aggregation: google.visualization.data.count
});
groupColumns.push({
column: i+1,
type: 'number',
//label: distinctValues[i],
aggregation: google.visualization.data.sum
});
}
But my aim is to create a pivot table something like as follows.
['Column1', 'Column2', 100, 200, 300, 400],
['A', 'bar', 0, 1, 1, 0],
['A', 'baz', 0, 0, 1, 0],
['A', 'foo', 3, 1, 0, 0],
['B', 'baz', 0, 1, 0, 0],
['B', 'cad', 1, 0, 1, 1],
['B', 'qud', 1, 1, 1, 2]
How can I proceed?
You have to change a few things in your code. First, the viewColumns needs to contain both columns 0 and 1 to start if you want Column1 and Column2 to both be in the output. Then, you need to adjust the columns you add to the viewColumns: each one needs a calc parameter which calculates the value in the column. In this case, you want to compare the value of the column to distinctValues[i] and return 1 when they match and 0 when they don't. In the aggregation function for groupColumns, use sum instead of count:
Then, in the grouping function, pass columns 0 and 1 in the first array:
var pivotedData = google.visualization.data.group(view, [0, 1], groupColumns);
See these changes working here: http://jsfiddle.net/asgallant/DUn6B/1/