Parsing local xml file in android

Question

Hii every one, am brand new to android,i have a doubt can any one help me

In this following link

http://www.androidpeople.com/android-xml-parsing-tutorial-using-saxparser/

there is a sax parser in which xml file is taken from the internet, using a URL path How to change that url to local path in which xml is stored in raw folder of the project,,can any one give me the syntax ,,thanx in advance

Answer 1

In the link you provided, replace the line 47

xr.parse(new InputSource(sourceUrl.openStream()));

with

xr.parse(getResources().getAssets().open(fileName));

and place your xml file in /res/raw folder

links: Asset Manager Docs and Resources Manager Docs

Answer 2

try {
//          InputStream is = getResources().getAssets().open("yourfilename.xml");
            InputStream is =getAssets().open("yourfilename.xml");
            SAXParserFactory spf = SAXParserFactory.newInstance();
            SAXParser sp = spf.newSAXParser();
            XMLReader xr = sp.getXMLReader();

            MyXMLHandler myXMLHandler = new MyXMLHandler();
            xr.setContentHandler(myXMLHandler);

            xr.parse(new InputSource(is));

        } catch (Exception e) {
            System.out.println("XML Pasing Excpetion = " + e);
        }

Answer 3

This is what I did,

InputStream is = res.openRawResource(R.raw.fileName);
xr.parse(new InputSource(is));

Answer 4

In Android you can store data in the assets folder, which can be entered by your code. To address your file use

file:///android_asset/yourFile.xml

I haven´t tried this yet, but I hope it will work