Android: Retrieve Name, Phone Number, Email, Birth

Question

I am getting only name & birthday using the code below. But I need phone number & email also. It would be great if anyone can help me out. Thanks.

private void getContacts() {
    Uri uri = ContactsContract.Data.CONTENT_URI;

    String[] projection = new String[]{
            ContactsContract.Contacts.DISPLAY_NAME,
            ContactsContract.CommonDataKinds.Event.CONTACT_ID,
            ContactsContract.CommonDataKinds.Phone.NUMBER,
            ContactsContract.CommonDataKinds.Email.DATA,
            ContactsContract.CommonDataKinds.Event.START_DATE
    };

    String where = ContactsContract.Data.MIMETYPE + "= ? AND " +
            ContactsContract.CommonDataKinds.Event.TYPE + "=" +
            ContactsContract.CommonDataKinds.Event.TYPE_BIRTHDAY;
    String[] selectionArgs = new String[]{
            ContactsContract.CommonDataKinds.Event.CONTENT_ITEM_TYPE
    };
    String sortOrder = null;
    ContentResolver contentResolver = this.getActivity().getContentResolver();
    Cursor cursor = contentResolver.query(uri, projection, where, selectionArgs, sortOrder);

    int nameColumn = cursor.getColumnIndex(ContactsContract.Contacts.DISPLAY_NAME);
    int numberColumn = cursor.getColumnIndex(ContactsContract.CommonDataKinds.Phone.NUMBER);
    int emailColumn = cursor.getColumnIndex(ContactsContract.CommonDataKinds.Email.DATA);
    int bithDayColumn = cursor.getColumnIndex(ContactsContract.CommonDataKinds.Event.START_DATE);
    while (cursor.moveToNext()) {
        String name = cursor.getString(nameColumn);
        String number = cursor.getString(numberColumn);
        String email = cursor.getString(emailColumn);
        String birthDay = cursor.getString(bithDayColumn);
        Log.d(TAG, "Birthday: " + birthDay);
    }
}

Answer 1

In your projection you're limiting your query to rows of MIMETYPE CommonDataKinds.Event.CONTENT_ITEM_TYPE only, so you'll only get birthdays.

You need to ask for emails and phones mimetypes, but note that these additional information will come in separate rows for the same contact. For example, for contact A that has 2 phones, 3 emails and a birthday, you'll get 6 results in your cursor. So you need to group them all together using the CONTACT_ID field.

Here's simple code to get you started, print the resulting HashMap and you'll get for each contact all his/hers name, emails, phones and birthday:

Map<Long, List<String>> contacts = new HashMap<Long, List<String>>();

String[] projection = {Data.CONTACT_ID, Data.DISPLAY_NAME, Data.MIMETYPE, Data.DATA1, Data.DATA2, Data.DATA3};

// query only emails/phones/events
String selection = Data.MIMETYPE + " IN ('" + Phone.CONTENT_ITEM_TYPE + "', '" + Event.CONTENT_ITEM_TYPE"', '" + Email.CONTENT_ITEM_TYPE + "')";
ContentResolver cr = getContentResolver();
Cursor cur = cr.query(Data.CONTENT_URI, projection, selection, null, null);

while (cur != null && cur.moveToNext()) {
    long id = cur.getLong(0);
    String name = cur.getString(1); // full name
    String mime = cur.getString(2); // type of data (phone / birthday / email)
    String data = cur.getString(3); // the actual info, e.g. [phone]

    String kind = "unknown";

    switch (mime) {
        case Phone.CONTENT_ITEM_TYPE: 
            kind = "phone"; 
            break;
        case Event.CONTENT_ITEM_TYPE: 
            kind = "birthday";
            break;
        case Email.CONTENT_ITEM_TYPE: 
            kind = "email";
            break;
    }
    Log.d(TAG, "got " + id + ", " + name + ", " + kind + " - " + data);

    // add info to existing list if this contact-id was already found, or create a new list in case it's new
    List<String> infos;
    if (contacts.containsKey(id)) {
        infos = contacts.get(id);
    } else {
        infos = new ArrayList<String>();
        infos.add("name = " + name);
        contacts.put(id, infos);
    }
    infos.add(kind + " = " + data);
}