How can I define operators so that a array of user

Question

I give the following code to illustrate my question:

#include <vector>

struct Complex
{
     int a, b, c;

     Complex() : a(3), b(4), c(10) {}

     operator int() const {  return a+b+c; }
};

int main()
{
   Complex abc;
   int value = (abc);
   Complex def;
   def.a = 20;
   int value2 = (def);

   std::vector<Complex> ar;
   ar.push_back(abc);
   ar.push_back(def);

   std::vector<int> ar2;
   ar2.push_back(abc);
   ar2.push_back(def);

   std::vector<int> ar3;
   ar3 = (ar);
}

This won't compile, due to the expression ar3 = (ar). I have declared a conversion operator so that the Complex class can be used in where int is expected. Can I also make it work for assigning an array of Complex objects to an array of int?

I tried to declare a non-member conversion operator for array of Complex, but that's not allowed:

void std::vector<int> operator = (std::vector<Complex> complexArray)
{
    std::vector<int> abc;
    for(int i=0; i<complexArray.size(); i++)
     abc.push_back(complexArray[i]);
    return abc;
}

Answer 1

Forget about automatic implicit conversion (at least for the Standard Library containers). But if you are willing to accept an explicit conversion like in the below example

 const std::vector<int> vi {1, 2, 3, 4, 5};
 const std::vector<double> vd = container_cast(vi);

then the implementation of the container_cast() utility follows. Note that it can cast not only between instantiations of the same template container for different element types (i.e. std::vector<int> to std::vector<double>), but also between different containers (e.g. std::vector to std::list).

#include <iostream>
#include <vector>
#include <list>

template<class SourceContainer>
class ContainerConverter
{
    const SourceContainer& s_;
public:
    explicit ContainerConverter(const SourceContainer& s) : s_(s) {}

    template<class TargetContainer>
    operator TargetContainer() const
    {
        return TargetContainer(s_.begin(), s_.end());
    }
};

template<class C>
ContainerConverter<C> container_cast(const C& c)
{
    return ContainerConverter<C>(c);
}

template<class C>
void printContainer(const C& c)
{
    std::cout << "{ ";
    for( auto x : c )
        std::cout << x << ' ';
    std::cout << "}" << std::endl;
}

int main()
{
    const std::vector<double> vd {2.2, 7.7, 5.5, 1.1, -4.4};
    printContainer(vd);

    const std::vector<int> vi = container_cast(vd);
    printContainer(vi);

    const std::list<float> lf = container_cast(vd);
    printContainer(lf);
    return 0;
}

Answer 2

You may consider the range constructor of std::vector.

std::vector<int> ar3(begin(ar), end(ar));

Answer 3

Whenever you want to transform something, the std::transform function might be good to use.

In your case you could do something like

// Create the new vector with the same size as the complex vector
std::vector<int> abc(complexArray.size());

std::transform(std::begin(complexVector), std::end(complexVector),
               std::begin(abc),
               [](Complex const& complex)
               {
                   int result;

                   // Code here that converts the complex structure to an integer
                   // and stores the integer in the variable result

                   return result;
               });

After the std::transform call above (once you complete it with the code to actually do the structure transformation) the vector abc will contain all the converted integers from the Complex structures in the source vector complexVector.