Overloading operator<<: cannot bind ‘std::ba

2019-03-01 03:40发布

Searching for the title of this question gives me a number of people quoting the same error, but under different circumstances, and unfortunately the answers there provided are specific to their situation, and I do not see how they can help me.

I am trying to overload operator<< for a template class. Following is a test case:

Vector.h:

#ifndef __INCL_VECTOR_H__
#define __INCL_VECTOR_H__

#include <array>

template < class T, unsigned int N >
class Vector
{
public:
    Vector();
    Vector( std::array< T, N > );

    template < class U, unsigned int M > friend Vector< U, M > operator+ ( const Vector< U, M >&, const Vector< U, M >& );

    template < class U, unsigned int M > friend std::ostream& operator<< ( std::ostream&, Vector< U, M >& );

    T& operator[] ( const unsigned int& );

protected:
    std::array< T, N > _values;
};

#include "Vector.hpp"

#endif

Vector.hpp:

#include "Vector.h"
#include <iostream>

template < class T, unsigned int N >
Vector< T, N >::Vector()
{
}

template < class T, unsigned int N >
Vector< T, N >::Vector( std::array< T, N > otherArray )
{
    _values = *( new std::array< T, N >( otherArray ) );
}

template < class U, unsigned int M >
Vector< U, M > operator+ ( const Vector< U, M > &lhVector, const Vector< U, M > &rhVector )
{
    Vector< U, M > sumVector;

    for( unsigned int i = 0; i < M; i++ )
        sumVector[i] = lhVector[i] + rhVector[i];

    return sumVector;
}

template < class U, unsigned int M >
std::ostream& operator<< ( std::ostream &out, Vector< U, M > &cVector )
{
    out << "< ";

    for( int i = M - 1; i >= 0; i-- )
    {
        out << cVector[i];
        if( i )
            out << ", ";
    }

    out << " >";

    return out;
}

template < class T, unsigned int N >
T& Vector< T, N >::operator[] ( const unsigned int &index )
{
    return _values[ index ];
}

vectorTest.cpp:

#include "Vector.h"

#include <iostream>
#include <array>

using namespace std;

int main( int argc, char* argv[] )
{
    Vector< int, 3 > u( array< int, 3 > {  1, 4,  2 } );
    Vector< int, 3 > v( array< int, 3 > { -2, 3, -1 } );

    cout << "u = " << u << endl;
    cout << "v = " << v << endl;
    cout << "u + v = " << u + v << endl;

    return 0;
}

The line which causes the error is cout << "u + v = " << u + v << endl;; the previous two lines work as expected.

The error message is as follows (compiling as g++ -std=c++11 Vector.h vectorTest.cpp):

vectorTest.cpp: In function ‘int main(int, char**)’:
vectorTest.cpp:15:31: error: cannot bind ‘std::basic_ostream<char>’ lvalue to ‘std::basic_ostream<char>&&’
In file included from /usr/include/c++/4.7/iostream:40:0,
                 from Vector.hpp:2,
                 from Vector.h:34:
/usr/include/c++/4.7/ostream:600:5: error:   initializing argument 1 of ‘std::basic_ostream<_CharT, _Traits>& std::operator<<(std::basic_ostream<_CharT, _Traits>&&, const _Tp&) [with _CharT = char; _Traits = std::char_traits<char>; _Tp = Vector<int, 3u>]’
In file included from Vector.h:34:0:
Vector.hpp: In instantiation of ‘Vector<U, M> operator+(const Vector<U, M>&, const Vector<U, M>&) [with U = int; unsigned int M = 3u]’:
vectorTest.cpp:15:31:   required from here
Vector.hpp:40:9: error: passing ‘const Vector<int, 3u>’ as ‘this’ argument of ‘T& Vector<T, N>::operator[](const unsigned int&) [with T = int; unsigned int N = 3u]’ discards qualifiers [-fpermissive]
Vector.hpp:40:9: error: passing ‘const Vector<int, 3u>’ as ‘this’ argument of ‘T& Vector<T, N>::operator[](const unsigned int&) [with T = int; unsigned int N = 3u]’ discards qualifiers [-fpermissive]

I'm unable to understand what these error messages are telling me. I'd appreciate any assistance.

标签: c++ g++
2条回答
男人必须洒脱
2楼-- · 2019-03-01 04:22

Change this:

std::ostream& operator<< ( std::ostream&, Vector< U, M >& );

to this:

std::ostream& operator<< ( std::ostream&, const Vector< U, M >& );
//                                        ^^^^^

The compiler is telling you that C++ will not let you bind a temporary Vector such as u + v to a non-const Vector&.

And you don't modify that Vector, so it should be const to begin with.

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别忘想泡老子
3楼-- · 2019-03-01 04:44

FIRST PROBLEM:

To make your program compile, just use an lvalue reference to const as the second parameter of your operator << (both in the friend-declaration and in the definition of that function):

template < class U, unsigned int M >
std::ostream& operator<< ( std::ostream &out, Vector< U, M > const& cVector )
//                                                           ^^^^^

The reason why your program won't compile is that your overload of operator << accepts an lvalue reference to non-const as its second argument, and lvalue references to non-const cannot bind to rvalues.

Since the result of operator + between two instances of Vector is a temporary, and a temporary is an rvalue, the compiler can't invoke your operator <<, and is therefore unable to resolve the call.

SECOND PROBLEM:

Once you fixed the above issue, you'll have to solve a second one: your Vector class template does not provide a const version of operator [], so your rewritten operator <<, which now accepts a reference to a const vector, won't be able to access the vector's elements.

template < class T, unsigned int N >
class Vector
{
    // ...

    T& operator[] ( const unsigned int& );

    T const& operator[] ( const unsigned int& ) const; // <== ADD THIS!

    // ...
};

And of course the corresponding definition:

template < class T, unsigned int N >
T const& Vector< T, N >::operator[] ( const unsigned int &index ) const
{
    return _values[ index ];
}
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