Simplest way to increment a date in PHP?

Question

Say I have a string coming in, "2007-02-28", what's the simplest code I could write to turn that into "2007-03-01"? Right now I'm just using strtotime(), then adding 24*60*60, then using date(), but just wondering if there is a cleaner, simpler, or more clever way of doing it.

Answer 1

It's cleaner and simpler to add 86400. :)

The high-tech way is to do:

$date = new DateTime($input_date);
$date->modify('+1 day');
echo $date->format('Y-m-d');

but that's really only remotely worthwhile if you're doing, say, a sequence of transformations on the date, rather than just finding tomorrow.

Answer 2

The simplest way...

echo date('Y-m-d',strtotime("+1 day"));    //from today

OR from specified date...

echo date('Y-m-d',strtotime("+1 day", strtotime('2007-02-28')));

Answer 3

$your_date = strtotime("1month", strtotime(date("Y-m-d")));
 $new_date = date("Y-m-d", $your_date++);

Answer 4

Hello you can try this below especially if you are french

$date = date('l j F Y');
#increment the date
$date2 = date('l j F Y', strtotime("+7 day"));

to translate in french you can use the setlocale() function or the function below :

function fr_date($date){

    $date = explode(' ', $date);

    $date = str_replace('Monday','Lundi',$date);
    $date = str_replace('Tuesday','Mardi',$date);
    $date = str_replace('Wednesday','Mercredi',$date);
    $date = str_replace('Thursday','Jeudi',$date);
    $date = str_replace('Friday','Vendredi',$date);
    $date = str_replace('Saturday','Samedi',$date);
    $date = str_replace('Sunday','Dimanche',$date);

    $date = str_replace('January','Janvier',$date);
    $date = str_replace('February','Février',$date);
    $date = str_replace('March','Mars',$date);
    $date = str_replace('April','Avril',$date);
    $date = str_replace('May','Mai',$date);
    $date = str_replace('June','Juin',$date);
    $date = str_replace('July','Juillet',$date);
    $date = str_replace('August','Août',$date);
    $date = str_replace('September','Septembre',$date);
    $date = str_replace('October','Octobre',$date);
    $date = str_replace('November','Novembre',$date);
    $date = str_replace('December','Décembre',$date);

    $date = implode(' ',$date);
    return $date;

}

Answer 5

 $early_start_date = date2sql($_POST['early_leave_date']);


        $date = new DateTime($early_start_date);
        $date->modify('+1 day');


        $date_a = new DateTime($early_start_date . ' ' . $_POST['start_hr'] . ':' . $_POST['start_mm']);
        $date_b = new DateTime($date->format('Y-m-d') . ' ' . $_POST['end_hr'] . ':' . $_POST['end_mm']);

        $interval = date_diff($date_a, $date_b);

Answer 6

Another way is to use function mktime(). It is very useful function...

$date = "2007-02-28";
list($y,$m,$d)=explode('-',$date);
$date2 = Date("Y-m-d", mktime(0,0,0,$m,$d+1,$y));

but I think strtotime() is better in that situation...