What is ?: in PHP 5.3? [duplicate]

Question

Possible Duplicate: What are the PHP operators “?” and “:” called and what do they do?

From http://twitto.org/

<?PHP
    require __DIR__.'/c.php';
    if (!is_callable($c = @$_GET['c'] ?: function() { echo 'Woah!'; }))
        throw new Exception('Error');
    $c();
?>

Twitto uses several new features available as of PHP 5.3:

1. The DIR constant
2. The ?: operator
3. Anonymous functions

---

1. What does number 2 do with the ?: in PHP 5.3?

2. Also, what do they mean by anonymous functions? Wasn't that something that has existed for a while?

Answer 1

?: is a form of the conditional operator which was previously available only as:

expr ? val_if_true : val_if_false

In 5.3 it's possible to leave out the middle part, e.g. expr ?: val_if_false which is equivalent to:

expr ? expr : val_if_false

From the manual:

Since PHP 5.3, it is possible to leave out the middle part of the conditional operator. Expression expr1 ?: expr3 returns expr1 if expr1 evaluates to TRUE, and expr3 otherwise.

Answer 2

Look here:

Since PHP 5.3, it is possible to leave out the middle part of the ternary operator. Expression expr1 ?: expr3 returns expr1 if expr1 evaluates to TRUE, and expr3 otherwise.

Anonymous functions: No, they didn't exist before 5.3.0 (see the first note below the examples), at least in this way:

function ($arg) { /* func body */ }

The only way was create_function(), which is slower, quite cumbersome and error prone (because of using strings for function definitions).

Answer 3

The ?: operator is the conditional operator (often refered to as the ternary operator):

The expression (expr1) ? (expr2) : (expr3) evaluates to expr2 if expr1 evaluates to TRUE, and expr3 if expr1 evaluates to FALSE.

In the case of:

expr1 ?: expr2

The expression evaluates to the value of expr1 if expr1 is true and expr2 otherwise:

Since PHP 5.3, it is possible to leave out the middle part of the ternary operator. Expression expr1 ?: expr3 returns expr1 if expr1 evaluates to TRUE, and expr3 otherwise.