this works in the desired way:
class d:
def __init__(self,arg):
self.a = arg
def p(self):
print "a= ",self.a
x = d(1)
y = d(2)
x.p()
y.p()
yielding
a= 1
a= 2
i've tried eliminating the "self"s and using a global statement in __init__
class d:
def __init__(self,arg):
global a
a = arg
def p(self):
print "a= ",a
x = d(1)
y = d(2)
x.p()
y.p()
yielding, undesirably:
a= 2
a= 2
is there a way to write it without having to use "self"?
When you remove the self's, you end up having only one variable called
a
that will be shared not only amongst all yourd
objects but also in your entire execution environment. You can't just eliminate the self's for this reason.Python methods are just functions that are bound to the class or instance of a class. The only difference is that a method (aka bound function) expects the instance object as the first argument. Additionally when you invoke a method from an instance, it automatically passes the instance as the first argument. So by defining
self
in a method, you're telling it the namespace to work with.This way when you specify
self.a
the method knows you're modifying the instance variablea
that is part of the instance namespace.Python scoping works from the inside out, so each function (or method) has its own namespace. If you create a variable
a
locally from within the methodp
(these names suck BTW), it is distinct from that ofself.a
. Example using your code:Which yields:
Lastly, you don't have to call the first variable
self
. You could call it whatever you want, although you really shouldn't. It's convention to define and referenceself
from within methods, so if you care at all about other people reading your code without wanting to kill you, stick to the convention!Further reading:
"self" is the way how Python works. So the answer is: No! If you want to cut hair: You don't have to use "self". Any other name will do also. ;-)