How to remove all characters after a specific char

Question

I have a string. How do I remove all text after a certain character? (In this case ...)
The text after will ... change so I that's why I want to remove all characters after a certain one.

Answer 1

another easy way using re will be

import re, clr

text = 'some string... this part will be removed.'

text= re.search(r'(\A.*)\.\.\..+',url,re.DOTALL|re.IGNORECASE).group(1)

// text = some string

Answer 2

If you want to remove everything after the last occurrence of separator in a string I find this works well:

<separator>.join(string_to_split.split(<separator>)[:-1])

For example, if string_to_split is a path like root/location/child/too_far.exe and you only want the folder path, you can split by "/".join(string_to_split.split("/")[:-1]) and you'll get root/location/child

Answer 3

Without a RE (which I assume is what you want):

def remafterellipsis(text):
  where_ellipsis = text.find('...')
  if where_ellipsis == -1:
    return text
  return text[:where_ellipsis + 3]

or, with a RE:

import re

def remwithre(text, there=re.compile(re.escape('...')+'.*')):
  return there.sub('', text)

Answer 4

Assuming your separator is '...', but it can be any string.

text = 'some string... this part will be removed.'
head, sep, tail = text.partition('...')

>>> print head
some string

If the separator is not found, head will contain all of the original string.

The partition function was added in Python 2.5.

partition(...) S.partition(sep) -> (head, sep, tail)

Searches for the separator sep in S, and returns the part before it,
the separator itself, and the part after it.  If the separator is not
found, returns S and two empty strings.

Answer 5

Split on your separator at most once, and take the first piece:

sep = '...'
rest = text.split(sep, 1)[0]

You didn't say what should happen if the separator isn't present. Both this and Alex's solution will return the entire string in that case.