C++ convert hex string to signed integer

Question

I want to convert a hex string to a 32 bit signed integer in C++.

So, for example, I have the hex string "fffefffe". The binary representation of this is 11111111111111101111111111111110. The signed integer representation of this is: -65538.

How do I do this conversion in C++? This also needs to work for non-negative numbers. For example, the hex string "0000000A", which is 00000000000000000000000000001010 in binary, and 10 in decimal.

Answer 1

Andy Buchanan, as far as sticking to C++ goes, I liked yours, but I have a few mods:

template <typename ElemT>
struct HexTo {
    ElemT value;
    operator ElemT() const {return value;}
    friend std::istream& operator>>(std::istream& in, HexTo& out) {
        in >> std::hex >> out.value;
        return in;
    }
};

Used like

uint32_t value = boost::lexical_cast<HexTo<uint32_t> >("0x2a");

That way you don't need one impl per int type.

Answer 2

Here's a simple and working method I found elsewhere:

string hexString = "7FF";
int hexNumber;
sscanf(hexString.c_str(), "%x", &hexNumber);

Please note that you might prefer using unsigned long integer/long integer, to receive the value. Another note, the c_str() function just converts the std::string to const char* .

So if you have a const char* ready, just go ahead with using that variable name directly, as shown below [I am also showing the usage of the unsigned long variable for a larger hex number. Do not confuse it with the case of having const char* instead of string]:

const char *hexString = "7FFEA5"; //Just to show the conversion of a bigger hex number
unsigned long hexNumber; //In case your hex number is going to be sufficiently big.
sscanf(hexString, "%x", &hexNumber);

This works just perfectly fine (provided you use appropriate data types per your need).