Method overloading with argument vararg of object

2019-02-26 11:31发布

If I attempt to overload the method flexiPrint() in a class Varargdemo then it generates a compile time error. The compiler treats the following signatures the same:

public static void flexiPrint(Object... data){}
public static void flexiPrint(Object[] data){}

Can someone explain to me why they are treated the same? I haven't been able to find the answer.

3条回答
祖国的老花朵
2楼-- · 2019-02-26 11:55

They are the same "under the hood". varargs (the ...) passes an array as a parameter:

It is still true that multiple arguments must be passed in an array, but the varargs feature automates and hides the process. Furthermore, it is upward compatible with preexisting APIs.

You can find it in the documentation here .

查看更多
小情绪 Triste *
3楼-- · 2019-02-26 11:58

Variable Length Arguments, like Object... are syntactic sugar. When used, for example:

flexiPrint("apple", "peach", "plum");

Then "apple", "peach", "plum" are actually turned into: `Object[]{"apple", "peach", "plum"}.

查看更多
Melony?
4楼-- · 2019-02-26 11:59

Object... is nothing but it is an array, that means same as defining Object[]

... (three dots) represents varargs in java.

We usually see this signature in main method like main(String... args)

So, having more than one method with same signature is not allowed in a class (compile time error). That is why you are seeing compile time error.

查看更多
登录 后发表回答